Answer:
Ix = Iy = 
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is 
. Moment of inertia of quarter disk about its perpendicular is 
.
Now using perpendicular axis theorem, Ix = Iy = 
= .
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Sarah spent $1,083 because $57*38=$2,166 and $2,166/2=$1083
10.5 hours
let t be time then distance travelled by both is
Mr Burges ⇔ d = 50t ( distance = speed × time )
Mrs Burges ⇒ d = 70(t - 3)
At the point of overtaking both will have travelled the same distance
equating their distance and solving for t
70(t - 3) = 50t
70t - 210 = 50t ( subtract 50t from both sides )
20t - 210 = 0 ( add 210 to both sides )
20t = 210 ( divide both sides by 20 )
t = 10.5 hours
Answer:
<h2>46•18</h2>
Step-by-step explanation:
<h3> I=PRT/100</h3><h2> 6740×<u>1</u><u>0</u>×7</h2><h2> 100</h2><h2> 674×1×7</h2><h2> 4618</h2><h2>the nearest hundredth is a 46•18 this is my answer</h2>
