Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.
1. x = ?
2. m∠MKL = ?
3. m∠JKL = ?
Answer/Step-by-step explanation:
Given:
m<JKM = 43,
m<MKL = (8x - 20),
m<JKL = (10x - 11).
Required:
1. Value of x
2. m<MKL
3. m<JKL
Solution:
1. Value of x:
m<JKL = m<MKL + m<JKM (angle addition postulate)
Therefore:
![(10x - 11) = (8x - 20) + 43](https://tex.z-dn.net/?f=%20%2810x%20-%2011%29%20%3D%20%288x%20-%2020%29%20%2B%2043%20)
Solve for x
![10x - 11 = 8x - 20 + 43](https://tex.z-dn.net/?f=%2010x%20-%2011%20%3D%208x%20-%2020%20%2B%2043%20)
![10x - 11 = 8x + 23](https://tex.z-dn.net/?f=%2010x%20-%2011%20%3D%208x%20%2B%2023%20)
Subtract 8x from both sides
![10x - 11 - 8x = 8x + 23 - 8x](https://tex.z-dn.net/?f=%2010x%20-%2011%20-%208x%20%3D%208x%20%2B%2023%20-%208x%20)
![2x - 11 = 23](https://tex.z-dn.net/?f=%202x%20-%2011%20%3D%2023%20)
Add 11 to both sides
![2x - 11 + 11 = 23 + 11](https://tex.z-dn.net/?f=%202x%20-%2011%20%2B%2011%20%3D%2023%20%2B%2011%20)
![2x = 34](https://tex.z-dn.net/?f=%202x%20%3D%2034%20)
Divide both sides by 2
![\frac{2x}{2} = \frac{34}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2x%7D%7B2%7D%20%3D%20%5Cfrac%7B34%7D%7B2%7D%20)
![x = 17](https://tex.z-dn.net/?f=%20x%20%3D%2017%20)
2. m<MKL = 8x - 20
Plug in the value of x
m<MKL = 8(17) - 20 = 136 - 20 = 116°
3. m<JKL = 10x - 11
m<JKL = 10(17) - 11 = 170 - 11 = 159°
Answer:
The percent of increase from 260 bagged handlers to 299 baggage handlers is 15%.
Hope I helped!
3.0*10^2= .03 this is a possible answer