Answer:
52.2g of KCl would be left
The mass of KCl will remain despite the solution is been heated
Explanation:
When you are heating a solution, just the solvent (In this case, water), will be evaporated and, in theory, the mass of KCl will remain despite the solution is been heated.
Now, the mass of KCl that you can obtain from 350mL of a 2.0M solution will be:
<em>Moles KCl:</em>
350mL = 0.350L * (2.0mol / L) = 0.700 moles
<em>Mass KCl -Molar mass: 74.55g/mol-:</em>
0.700mol * (74.55g/mol) = 52.2g of KCl would be left
0.04350179862
Explanation:
Make sure to check for sig figs though. Basically, you have 2.54 mL and you multiply that by the 0.789 g/mL and mL cancels out and you are left with 2.00406g. There are 46.06844 grams per mol of ethanol, so to cancel out grams we multiply by 1/46.06844. And then we are left with 0.04350179862 mol
Answer:
0.366 moles to the nearest thousandth.
Explanation:
The molar mass of acetic acid CH3COOH = 2*12 + 4(1.008) + 2*16
= 60.03 g so the number of moles in 22 g
= 0.366.
Hey there!
Answer: Protons
The atom in a sample of an element must contain nuclei with the same number of protons. If the protons change in number, then the element will modify as well.
Thank you!
Xe +f2 →Xef2
ΔXe = ΣB.P reactants - Σ B.d products
-108k.s/ mol = B. D f₂ - 2 B.D xe-f
-108 k.s/mol =155 k.s/mol - 2B.Dxe-f
263kJ/mol/2 = B. D xe-f
B.D xef = 131.5 kJ/mol
132 kJ/mol
