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Bezzdna [24]
3 years ago
15

A line with a slope of -2 crosses the y-axis at (0, 3). The equation of the line is _______

Mathematics
2 answers:
Gekata [30.6K]3 years ago
7 0
In y = mx + b form, the slope is in the m position and the y int is in the b position
u have a slope of -2 and a y int of 3

so ur equation is : y = -2x + 3...but we need it in standard form

y = -2x + 3.....add 2x to both sides
2x + y = 3 <== ur equation
Arisa [49]3 years ago
4 0
The point (0,3)  is the y intercept of the line. y - intercelt is at y=3.

So we can use the slope intercept form of the straight line y = mx + b:-

y = -2x + 3

or 
2x + y = 3


Its c).
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Can you find x I don’t know how.
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3 0
3 years ago
A student solved 6x+4=2(x−8) in four steps as shown:
mr_godi [17]
The first thing you should do is solve the equation yourself.

1) Distribute the 2.  
6x + 4 = 2x – 16

2) Next, you'll want to get the x's on one side. So add -2x to both sides.
6x + 4 + -2x = 2x + -2x - 16
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3) Now subtract 4 from both sides
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4) Finally, divide both sides by 4
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To solve this problem all you need to do is look back out you work, and figure out the correct solution. The answer the question is The student made an error in Step 1.

7 0
3 years ago
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sp2606 [1]

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Step-by-step explanation:

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