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Anna [14]
3 years ago
6

A rocket launches upward off of a 18 ft platform with an initial velocity of 125 ft/sec creating the equation begin mathsize 18p

x style p left parenthesis t right parenthesis equals negative 16 t squared plus 125 t plus 18 end style where p(t) represents the position of the rocket based on time, and t represents time.
What is a realistic range for this problem?
Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0
Um i this is not my level
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Edg vector operations, any help appreciated!
viktelen [127]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: Add \:\: -6 \hat i - 6\hat j \:\:with \:\; Vector \:\; c

____________________________________

\large \tt Solution  \: :

Vector d can be represented as :

\qquad \tt \rightarrow \:  - 2 \hat i - 2 \hat j

Vector c can be represented as :

\qquad \tt \rightarrow \:  4 \hat i + 4\hat j

we have to create vector d from vector c

So, let's assume a vector x, such that sum of vector x and vector c equals to vector d

\qquad \tt \rightarrow \: x + ( 4 \hat i + 4 \hat j) =  - 2 \hat i  - 2 \hat j

\qquad \tt \rightarrow \: x  = -  ( 4 \hat i + 4 \hat j)   - 2 \hat i  - 2 \hat j

\qquad \tt \rightarrow \: x  = (-   4 \hat i  - 2 \hat  i)  + (  - 4 \hat j  - 2 \hat j)

\qquad \tt \rightarrow \: x  = - 6 \hat  i    -6 \hat j

Henceforth, in order to get vector d, we need to add (-6i - 6j) in vector c

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0
2 years ago
Help me w this multiple choice!
olga2289 [7]

Answer:

D

Step-by-step explanation:

\sin(30)  =  \frac{n}{ \frac{10 \sqrt{3} }{3} }   \\ 0.5 =  \frac{n}{5.77} \\ n = 2.88 =  \frac{5 \sqrt{3} }{3}

\cos(30)  =  \frac{m}{ \frac{10 \sqrt{3} }{3} }  \\ 0.866 =  \frac{m}{5.77}  \\ m = 5

3 0
3 years ago
HELP FAST PLEASE!!!
Alisiya [41]

Answer:

y = -0.75x + 9.5

Step-by-step explanation:

Equation of a circle is given as :

(x-a)^{2} + (y-b)^2 = r^{2} \\(x-6)^{2} + (y-5)^2 = 4^{2}\\x^{2} - 12x + 36 + y^{2} -10y + 25 = 16\\x^{2} - 12x  + y^{2} -10y + 45 = 0\\

Take the derivative of the above with respect to x

2x - 12 + 2y dy/dx - 10 dy/dy = 0\\\frac{dx}{dy} = \frac{6 - x}{y-5} \\At (2,8) dy/dx = (6-2)/(8-5) = 4/3\\dy/dx = 4/3\\The slope of the tangent to the circle, m = \frac{-1}{dy/dx} \\m = \frac{-1}{4/3}\\m= -0.75

The equation of the tangent is given by :

y - y_{1} = m(x - x_{1})\\ y - 8 = -0.75(x - 2)\\y - 8 = -0.75x + 1.5\\y = -0.75x + 9.5

8 0
3 years ago
Read 2 more answers
!! WILL MARK BRAINLIEST PLZ HELP !!
Luba_88 [7]

Answer:

c

Step-by-step explanation:

.................................

5 0
2 years ago
Can someone please help me with this square root problem?
nadya68 [22]

Answer:

x=14.87

Step-by-step explanation:

What we want to use is pythagoras theorem:

a^2+b^2=c^2, where c is the hypotenuse

10^2+11^2=x^2

221=x^2

x=\sqrt{221}

x=14.866...

x=14.87

4 0
2 years ago
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