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3 years ago

382.993 to the nearest hundredth is what?

2 answers:

7 0

The answer is 383,000 because the hundreds is in the 900's so you can't just put 382,1,000 so the thousands place would have to go up one thousand so now the 2 becomes a 3 and the hundreds, tens, and ones place become 0's.

Natalija [7]3 years ago

3 0

Hundredth is the second decimal place so it should round to 382.99

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What is 82×68 this is very hard

zubka84 [21]

Answer:

5576

Step-by-step explanation:

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2 years ago

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Write one word problem using arithmetic sequences and another using geometric sequences.

Levart [38]

Hey There!

If i got this down right,
An = A1 + (n - 1)d
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3 years ago

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1. Find two numbers with a common factor of 3 only.

Mnenie [13.5K]

Answer:

All numbers can be written as a product of the prime numbers that conform them.

A) Find two numbers with a common factor of 3 only.

for example:

2*3 = 6

7*3 = 21

Both numbers have the factor 3 in them, and because the other two numbers are primes, we can be sure that the 3 is the only common factor.

B) Write a pair of numbers with a common factor of 2, 3 and 6.

Here we can write:

2*3*2 = 12

3*2*5 = 30

Those two numbers have the common factors 6, 2 and 3.

C) Write a pair of numbers with common factors of 3, 6 and 9.

3*2*3 = 18 (has the factors 2, 3, 3*2 = 6, 3*3 = 9)

-3*2*6 = -36

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8 0

3 years ago

Please help in this question. I WILL mark brainliest. NO LINKS

deff fn [24]

Answer:

B, you are correct

Area of the bigger trapezoid = (6 + 2) x 1/2 x 6 = 8 x 1/2 x 6 = 4 x 6 = 24

Area of the smaller trapezoid = (4 + 2) x 1/2 x 3 = 6 x 1/2 x 3 = 3 x 3 = 9

<h2>Area of the shaded area = 24 - 9 = 15</h2>

Hope that helps! :)

-Aphrodite

Step-by-step explanation:

6 0

3 years ago

A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

Finger [1]

Answer:

Fencing required = 1586 m

Step-by-step explanation:

The given statements can be thought of a triangle $\triangle ABC$ as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

$\angle A =49^\circ$

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use Cosine Rule to find the third side.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m$

Perimeter of the triangle = Sum of three sides = AB + BC + AC

Perimeter of the triangle = 435 + 495 + 656 = 1586 m

Fencing required = 1586 m

4 0

3 years ago