Step-by-step explanation:
2x+y=7
(A) (0,7),(72,0)and(3,1)
(B) (0,6),(72,0)and(3,1)
(C) (0,7),(52,0)and(3,1)
(D) (0,7),(72,0)and(2,1)
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Find three solutions of the equation: 2x+y=7
(A) (0,7),(72,0)and(3,1)
(B) (0,6),(72,0)and(3,1)
(C) (0,7),(52,0)and(3,1)
(D) (0,7),(72,0)and(2,1)
Given:
The linear equation having variables x and y is given as –
2x+y=7
For the initial solution of the equation, put x=0 in the linear equation and obtain the value of variable y .
So, substituting x=0 in the equation, we get,
2×0+y=7y=7
So, the first solution of the linear equation is
x=0
y=7
In two-dimensional coordinates form (x,y) , the first solution is (0,7) .
Now, similarly,
Substituting y=0 in the linear equation we have,
⇒2x+0=7⇒2x=7⇒x=72
So, the second solution of the linear equation is
x=72
y=0
In two-dimensional coordinates form (x,y) , the second solution is (72,0) .
And finally,
Substituting y=1 in the linear equation we have,
⇒2x+1=7⇒2x=6⇒x=62⇒x=3
So, the third solution of the linear equation is
x=3
y=1
In two-dimensional coordinates form (x,y) , the third solution is (3,1) .
Therefore, the three solutions of the equation 2x+y=7 are (0,7) , (72,0) and (3,1) .
The correct answer is –
(A) (0,7),(72,0)and(3,1)
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