Answer:
30/552
Step-by-step explanation:
In order to solve this problem you need to multiply the probability of getting grape for the first gumball with the probability of getting grape for the second gumball. Since there are 6 grape gumballs and a total of 24 gumballs (6*4). Then the probability of getting grape for the firs one is
Now there are only 5 grape gumballs available and one less in the total supply, therefore the probability of getting grape in the second try is
Finally we multiply them together to find the probability of getting two grapes in a row.
=
Answer: 5x (x-3) or 5(x^2-3x)
Step-by-step explanation:
A(t)=A0*(1/2)^(t/30)
where t=elapsed years
A0=initial mass at t=0.
Answer:
0.98046
Step-by-step explanation:
Given:
Here we are required to find
P(5.48 <X<5.82) and between 5.48 and 5.82 we each z-score given by
<em>z = (x - μ) / σ</em>
So 5.48 we have z = -2.714 and 5.82 we have z = 2.143
Therefore we have the area of interest on the normal distribution chart given by
:
P( -2,714 < z < 2.143)
= 1 - P(Z<-2.714) + P(Z > 2.143)
= 1 - P(Z<-2.714) + (1 - P(Z < 2.143))
= 1 - 0.00336 + 1 - 0.98382
= 1 - 0.01954 = 0.98046