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3 years ago

Determine whether the two lines are parallel, perpendicular or neither x-3y=6 y=3x+4

Mathematics

1 answer:

Anna [14]3 years ago

6 0

Answer:

neither

Here's how you know:

first, i'll simplify it so both are in slope-intercept form (y = mx + b).

x-3y=6

-3y = 6 - x

y = (1/3)x - 2

y=3x+4 is already in slope-intercept form, yay :)

these lines are neither parallel nor perpendicular.

The equations of parallel lines have THE SAME SLOPES (y = mx + b --> m would be exactly the same).

In contrast, perpendicular lines have NEGATIVE RECIPROCAL SLOPES (y = mx + b --> m would be -1/m).

--> since the slopes of these match neither of these definitions, we know it must be neither.

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A computer system requires that passwords contain at least one digit. if eight characters are generated at random, and each is e

KIM [24]

Figure this out as though no digits are present. You can choose 8 of the 26 letters and that's it.
26^8 [you can allow repeating letters] = 2.088 * 10^11
The total number of ways that can be chosen with letters and digits intermixed = 36^8

The probability of getting no numbers is 26^8 / 36^8 or (26/36)^8 = 0.07402
So the probability that there were be at least one digit is
1 - 0.07402 = 0.92598

6 0

3 years ago

What is the best estimate of 11 1/5÷2 3/4

likoan [24]

Answer:4

Step-by-step explanation:

5 0

3 years ago

X^2 + 7x – 18 = 0 a {–2, 9} b {–9, 2} c {2, 9} d {–2, –9}

Sedaia [141]

Answer:

b)-9,2

Step-by-step explanation:

x^2+7x-18=0

x^2+9x-2x-18=0

x(x+9)-2(x+9)=0

(x+9)(x-2)=0

therefore

x=-9

x=2

6 0

2 years ago

OK SO HERES THE PROBLEM. MY BRAIN HURTS. PLZZZ help me with this math problem

jeka57 [31]

Oh Foxy, Foxy, how totally debilitated you must be ! Try to relax. Nobody
enjoys a painful brain, and believe me, this problem is not worth it.

Let me put it to you this way: What if the problem said . . .

-- Demarcus has $8 more than his sister.
-- His sister has $4.
-- How much money ' M ' does Demarcus have ?

If your brain didn't hurt, you could quickly solve this right in there.
You would know that Demarcus' money ' M ' = 8 + 4 .

That's almost exactly what the problem does say.
Except it doesn't say he has "$8 more than his sister",
it says he has "at least" that much.
So you know that ' M ' is not exactly = 8 + 4, but that's the least it could be.
The actual amount of ' M ' is more than that.

Surely you can handle it from here, even with half of your brain
tied behind your back.

Take a good hard look at ' A ', and then go lie down.

7 0

2 years ago

A restaurant chain has two locations in a medium-sized town and, believing that it has oversaturated the market for its food, is

scoray [572]

Answer:

Yes, since the test statistic value is greater than the critical value.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=360000$ represent the mean for the downtown restaurant

$\bar X_{2}=340000$ represent the mean for the freeway restaurant

$s_{1}=50000$ represent the sample standard deviation for downtown

$s_{2}=40000$ represent the sample standard deviation for the freeway

$n_{1}=36$ sample size for the downtown restaurant

$n_{2}=36$ sample size for the freeway restaurant

t would represent the statistic (variable of interest)

$\alpha=0.05$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:

Null hypothesis: $\mu_{1}\leq \mu_{2}$

Alternative hypothesis: $\mu_{1} > \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Determine the critical value.

Based on the significance level $\alpha=0.05$ and $\alpha/2=0.025$ we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.

For this case the value is $t_{1-\alpha/2}=1.66$

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{360000-340000}{\sqrt{\frac{50000^2}{36}+\frac{40000^2}{36}}}}=1.874$

What is the p-value for this hypothesis test?

Since is a right tailed test the p value would be:

$p_v =P(t_{70}>1.874)=0.033$

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.

The best option would be:

Yes, since the test statistic value is greater than the critical value.

5 0

2 years ago