Answer:
No
Step-by-step explanation:
On a number line, the 0 is in the middle. Positive numbers are to the right of the 0 and negative numbers are to the left of the 0. A point farthest from 0 could be on the left side and therefore be really small. Therefore the point farthest from 0 is not always the greatest as it could also be the smallest
Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.
Answer:
w^8 - 4w^7 + 6w^6 - 4w^5 + w^4 .
Step-by-step explanation:
(w - w^2)^4
= w^4 ( 1 - w)^4
By the binomial theorem:
= w^4( 1 - 4w + 6w^2 - 4w^3 + w^4)
= w^4 - 4w^5 + 6w^6 - 4w^7 + w^8
= w^8 - 4w^7 + 6w^6 - 4w^5 + w^4 ( Standard form).
I say the answer is B. Bland
Answer:
I plotted it out on the graph and here it is:
