The solution for this problem is:
The population is 500 times bigger since 8000/24 = 500. The population after t days is computed by:P(t) = P₀·4^(t/49)
Solve for t: 8000 = 8·4^(t/49) 1000 = 4^(t/49) log₄(1000) = t/49t = 49log₄(1000) ≅ 244 days
All but the last one I think but don't quote me
3/16 as a decimal is 0.18
and 5/48 as a decimal is 0.10
SO
you have 0.10, 0.18, 0.75, and 0.5 so put that in order

Infinite solutions. This equality is true for any value of n.
a.