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lara [203]
3 years ago
14

If an atom has 2 electrons outside of its nucleus, which combination of protons and neutrons would result in a neutral atom?

Chemistry
1 answer:
Dahasolnce [82]3 years ago
8 0
It would be a llllllllllll
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A substance with a define shape and volume is a blank phase of metter
aksik [14]
Definite Shape and Definite Volume is a solid.

NO Definite Shape and Definite Volume is a liquid.

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4 0
3 years ago
A compound has an empirical formula of CH2 and a molar mass of 56 g. What is its molecular formula?
kipiarov [429]

Answer:

C4H8

Explanation:

First find the molar mass of CH2;

2(1.01) + 1(12.01) = 14.03g

Now divide the molar mass of the compound by the molar mass of CH2;

56g/14.03g = 3.9914 Round to nearest whole number = 4

Multiply CH2 by 4 to get the molecular formula;

CH2* 4 = C4H8

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A student calculated the density of a sample of graphite to be 2.3 g/cm3. Show a numerical setup for calculating the student’s p
LUCKY_DIMON [66]

Answer:

Percent error = 1.5%

Explanation:

Given data:

Measured value of density of graphite = 2.3 g/cm³

Percent error = ?

Solution:

Formula:

Percent error = [Measured value - Actual value / actual value] × 100

Actual/accepted value of density of graphite = 2.266 g/cm³

Now we will put the values:

Percent error = [2.3 g/cm³ - 2.266 g/cm³ / 2.266 g/cm³] × 100

Percent error = [0.034 g/cm³ / 2.266 g/cm³] × 100

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Percent error = 1.5%

8 0
3 years ago
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The base-dissociation constant, kb, for pyridine, c5h5n, is 1.4x10-9 the acid-dissociation constant, ka, for the pyridinium ion,
sp2606 [1]
We are given the base dissociation constant, Kb, for Pyridine (C5H5N) which is 1.4x10^-9. The acid dissociation constant, Ka for the Pyridium ion or the conjugate acid of Pyridine is to be determined. We know from our chemistry classes that:

Kw = Kb * Ka

where Kw is always equal to 1x10^-14

so, to solve for Ka of Pyridium ion, substitute Kb to the equation together with Kw and solve for Ka:

1x10^-14 = 1.4x10^-9 * Ka
solve for Ka

Ka = 7.14x10^-6 

Therefore, the acid dissociation constant of Pyridinium ion is 7.14x10^-6.
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