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shusha [124]
3 years ago
15

How many energy levels does this atom have

Chemistry
1 answer:
Bas_tet [7]3 years ago
8 0

Answer:

i feel like it would be four

Explanation:

Srr if i was wrong

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In systemic tissue fluids, the enzyme carbonic anhydrase catalyzes the reaction co2 + h2o → h2co3 (which then can dissociate int
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It is achievable for the same enzyme to catalyze reverse reactions for the reason that the direction of a reversible reaction is determined by the concentrations of reactants and products. In pulmonary circulation, the low CO2 concentration supports the making of CO2 and H2O.
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3 years ago
Determine the total time that must elapse until only ¼ of an original sample of the radioisotope Rn-222 remains unchanged.
Arte-miy333 [17]

Answer:

7.6 days

Explanation:

Radon is a radioactive element and Radon-222 is it's most stable isotope. The half-life of Radon-222 has been found to be approximately 3.8 days.

Let, the initial amount of the Rn-222 = 1 = A

Final amount = \frac{1}{4} = A'

We will use the following relation for calculating time elapsed in the decay

A' = A(\frac{1}{2} )^\frac{t}{t_1_/_2}  }

Thus,

\frac{1}{4} =1(\frac{1}{2} )^\frac{t}{3.8}

We can write is as,

(\frac{1}{2} )^2=(\frac{1}{2} )^\frac{t}{3.8}

Since the base in both sides are equal, powers can also be equal and thus,

2=\frac{t}{3.8}

So, t = 7.6 days

5 0
2 years ago
The first task you are assigned in your summer laboratory job is to prepare a concentrated naoh stock solution. the molecular we
tensa zangetsu [6.8K]

240 g NaOH

<em>Step 1</em>. Calculate the moles of NaOH

Moles of NaOH = 0.750 L solution × (8 mol NaOH/1 L solution) = 6 mol NaOH

Step 2. Calculate the mass of NaOH

Mass of NaOH = 6 mol NaOH × (40 g NaOH/1 mol NaOH) = 240 g NaOH

7 0
3 years ago
What elements on the periodic table are most likely to form molecular compounds?
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Alkaline Earth Metals and Alkali Reactive metals because they need more electrons to acquire octet.
4 0
3 years ago
A 2,000g of C-14 is left to decay radioactively. The half-life of Carbon-14 is approximately 5,700 years. What percentage of the
dsp73
Answer is: 12,6% (1/8) <span>percentage of the sample will remain.
</span>c₀ - initial amount of C-14.<span>
c - amount of C-14 remaining at time.
t = 5700</span> y.<span>
First calculate the radioactive decay rate constant λ:
λ = 0,693 ÷ t = 0,693 ÷ 5700</span> y = 0,000121 1/y = 1,21·10⁻⁴ y.
c = c₀·e∧-λ·t.
c = 2000 · e∧-(0,000121 1/y · 17100 y).
c = 252 g.
ω = 252 g ÷ 2000 g = 0,126 = 12,6%.
<span>

</span>
4 0
3 years ago
Read 2 more answers
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