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4 years ago

Which of the following compounds is more soluble in acidic solution than in pure neutral water?

Chemistry

1 answer:

alexandr1967 [171]4 years ago

5 0

Answer:

The compound A (BaCO₃) is the most soluble in acidic solution.

Explanation:

We analyze the dissociation of the compounds:

A) BaCO₃ ⇒ Ba⁺² + CO₃⁻²

CO₃⁻² is the conjugated base of HCO₃ acid, which is a weak acid, therefore its conjugate base is strong.

B) CuI ⇒ Cu⁺ + I⁻

I⁻ is the conjugated base of HI acid, which is a strong acid, therefore its conjugate base is weak.

C) PbCl₂ ⇒ Pb⁺² + 2 Cl⁻

Cl⁻ is the conjugated base of HCl acid, which is a strong acid, therefore its conjugate base is weak.

D) AgBr ⇒ Ag⁺ + Br⁻

Br⁻ is the conjugated base of HBr acid, which is a strong acid, therefore its conjugate base is weak.

E) NH₄NO₃ ⇒ NH₄⁺ + NO₃⁻

NO₃⁻ is the conjugated base of HNO₃ acid, which is a strong acid, therefore its conjugate base is weak.

As the medium is acidic, there is a high concentration of H₃O⁺ and the CO₃⁻² is a strong base, the concentration of CO₃⁻² decreases to form H₂CO₃ and by the Le Chatelier's principle the equilibrium of the dissociation reaction shifts to the right and increases the solubility of the salt.

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Ar (g) is placed in a 3.80 L container at 320 K. The gas pressure is 0.496 atm.

nata0808 [166]

Answer:

PV=nRt

Therefore n(number of moles)=PV/RT

=>(0.49×3.80)/(0.08206×320)

Therefore Number of moles is = 0.071mols

Explanation: By using the Real gas equation..

PV=NRT .

We can solve for the number of moles of Ar by making N the subject..

Always make sure you pressure is In atm, your Volume is in Litres and temperature in degree Kelvin.

Also Recall the universal gas constant R used in this type of questions which is 0.08206.

Hence l, by making N the subject we get our answer as

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4 years ago

What is the relationship between melting/boiling point and intermolecular forces

sattari [20]

Boiling points are a measure of intermolecular forces. The intermolecular forces increase with increasing polarization of bonds. Boiling point increases with molecular weight, and with surface area.

8 0

3 years ago

2NOCl(g) ↔ 2NO(g) + Cl2(g) with K = 1.6 x10–5. In an experiment, 1.00 mole of pure NOCl and 1.00 mole of pure Cl2 are placed in

poizon [28]

Answer: $3.8\times 10^{-3}M$

Explanation:

Moles of $NOCl$ = 1 mole

Moles of $Cl_2$ = 1 mole

Volume of solution = 1 L

Initial concentration of $NOCl$ = 1 M

Initial concentration of $Cl_2$ = 1 M

The given balanced equilibrium reaction is,

$2NOCl(g)\rightleftharpoons 2NO(g)+Cl_2(g)$

Initial conc. 1 M 0M 1 M

At eqm. conc. (1-2x) M (2x) M (1+x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[NO]^2[Cl_2]}{[NOCl]^2}$

The $K_c$ = $1.6\times 10^{-5}}$

Now put all the given values in this expression, we get :

${1.6\times 10^{-5}}=\frac{(2x)^2\times (1+x)}{(1-2x)^2}$

By solving the term 'x', we get :

$x=0.0019$

Concentration of $NO$ at equilibrium= (2x) M = $2\times 0.0019=3.8\times 10^{-3}M$

6 0

3 years ago

Which sub-atomic particle is positively charged and found in the nucleus?

Anarel [89]

The proton has a positive charge.

4 0

3 years ago

Select all of the following statements that are false about ΔGo and ΔG:a) If the reaction has a large negative ΔGo value, the re

OLEGan [10]

Answer:

a) If the reaction has a large negative ΔGo value, the reaction must reach equilibrium at a small extent of reaction value

d) ΔGo and ΔG have the same magnitude, they just have opposite signs.

Explanation:

The fraction of the total heat energy if a system that does useful work is known as Gibb's free energy (G) and the change from the initial to final state is designated by $\Delta G$ . It is observed that the values of $\Delta G$ changes with experimental conditions such as temperature , pressure , concentration etc.

$\Delta G^0$ is the standard free energy change which is a balance of two natural tendencies of any system.

Minimization of potential energy or enthalpic factor $\Delta H^0$

Maximization of disorderliness or entropic factor $T\Delta S^0$

Mathematically; $\Delta G$ = $\Delta H^0$ - $T\Delta S^0$

Thus; from above mentioned, the statements that are true about ΔG⁰ and ΔG are:

ΔG⁰ and ΔG can have different values, they don't even have to have the same sign

For a reaction that reaches equilibrium, the minimum value of free energy must be at the equilibrium point

If ΔG⁰ , measured at an extent of reaction = 0.5, is positive, the sign for ΔG when the extent of reaction = 0.80 is also positive.

while the false statements include:

a) If the reaction has a large negative ΔG⁰ value, the reaction must reach equilibrium at a small extent of reaction value

d) ΔG⁰ and ΔG have the same magnitude, they just have opposite signs.

7 0

3 years ago