Answer:
3–methyl–2–butanol
Explanation:
To name the compound, we must:
1. Identify the functional group.
2. Give the functional group of the compound the lowest possible count.
3. Locate the longest continuous carbon chain. This gives the parent name of the compound.
4. Identify the substituent group attached.
5. Give the substituent group the lowest possible count.
6. Combine the above to get the name of the compound.
Now, let us obtain the name of the compound.
1. The functional group of the compound is Alcohol i.e —OH.
2. The functional group is located at carbon 2.
3. The longest continuous carbon chain is carbon 4 i.e butane. But the presence of the functional group i.e OH will replace the –e in butane with –ol. Therefore, the compound is butanol.
4. The substituent group attached is methyl i.e CH3.
5. The substituent group is located at carbon 3.
6. Therefore, the name of the compound is:
3–methyl–2–butanol.
The % yield if 500 g of sulfur trioxide reacted with excess water to produce 575 g of sulfuric acid is calculated using the below formula
% yield = actual yield/ theoretical yield x100
actual yield =575 grams
to calculate theoretical yield
find the moles of SO3 used =mass/molar mass
= 500g/ 80 g/mol =6.25 moles
SO3+H2O=H2SO4
by use of mole ratio of SO3 : H2SO4 which is 1:1 the moles of H2SO4 is also= 6.25 moles
the theoretical yield of H2SO4 is therefore = moles /molar mass
= 6.25 x98= 612.5 grams
%yield is therefore= 575 g/612 g x100= 93.9 %
Answer:
6
Explanation:
The atomic number (chemical sombol) is 6
Answer:
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