Answer:
<em>The sample size 'n' = 721</em>
<em>Number of cars 'n' = 721</em>
Step-by-step explanation:
<u><em>Explanation</em></u>:-
<em>Given Population proportion 'p' = 0.40</em>
<em>Given Margin of error = 0.03</em>
<em>90% of level of significance </em>
<em> </em>
<em></em>
<em>The Margin of error is determined by</em>
<em></em>
<em></em>
on calculation , we get
0.03√n = 0.8058
squaring on both sides , we get
n = 721.45≅721
<u><em>conclusion</em></u>:-
<em>The sample size 'n' = 721</em>
<em>Number of cars 'n' = 721</em>
Answer:
Your question was a bit confusing so I found another related question. You can reference it with your own details.
A vendor bought 10 dozen eggs at the rate of Rs 22 per dozen. Six of the eggs were rotten. He sold the remaining eggs at the rate of Rs 2.50 per egg . Find his profit or loss
Vendor bought 10 dozen eggs which means the vendor bought:
= 10 * 12 eggs
= 120 eggs
6 were rotten and he sold the rest for Rs. 2.50 per egg.
= (120 - 6) * 2.5
= Rs. 285
The amount he spent on the eggs was:
= 10 dozen * 22
= Rs. 220
Profit = 285 - 220
= Rs. 65
3.8 / 1.9 = x / 7.6....3,8 miles to 1.9 miles = x miles to 7.6 miles
cross multiply
(1.9)(x) = (3.8)(7.6)
1.9x = 28.88
x = 28.88 / 1.9
x = 15.2 <== Cameron ran 15.2 miles
The answer to your question is Y
