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3 years ago

The function f(x)=-3cos(3x+Pi/4) has ___ .

Mathematics

1 answer:

Furkat [3]3 years ago

3 0

Answer:

amplitude = 3

period = $\frac{2\pi }{3}$

Step-by-step explanation:

Comparing the equation with the general equation :

$f(x) = A cos(Bx + c ) + D$

Where :

A = amplitude

period = $\frac{2\pi }{B}$

D = vertical shift

Therefore : with the comparison :

amplitude = /-3/ = 3

period = $\frac{2\pi }{3}$

You might be interested in

Name five fractions whose values are between 1/8 and 1/5

Volgvan

Answer:

1/5

1. 1/56

2. 1/6

3. 1/65

4. 1/7

5. 1/75

1/8

Step-by-step explanation:

The fractions I gave (1/56, 1/6, 1/65, 1/7, 1/75) are all in between 1/5 and 1/8.

A way to think about this is to add a zero to a denominator of 1/5 and 1/8 and turn them into whole numbers:

1/5 --> 1/50 --> 50

1/8 --> 1/80 --> 80

Then find number between them:

55, 60, 65, 70, 75

Then, turn them into a fraction with a 1 as the numerator and the number as denominators:

1/55, 1/60, 1/65, 1/70, 1/75

This is the process. These numbers are all in between 1/5 and 1/8.

I hope this helps you!

(P.S., I don't think this works with negative numbers, though)

6 0

3 years ago

Read 2 more answers

What is the exact value of cos (67.5°)?

babymother [125]

first off, make sure you have a Unit Circle, if you don't do get one, you'll need it, you can find many online.

let's double up 67.5°, that way we can use the half-angle identity for the cosine of it, so hmmm twice 67.5 is simply 135°, keeping in mind that 135° is really 90° + 45°, and that whilst 135° is on the 2nd Quadrant and its cosine is negative 67.5° is on the 1st Quadrant where cosine is positive, so

$cos(\alpha + \beta)= cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta) \\\\\\ cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}} \\\\[-0.35em] ~\dotfill\\\\ cos(135^o)\implies cos(90^o+45^o)\implies cos(90^o)cos(45^o)~~ - ~~sin(90^o)sin(45^o) \\\\\\ \left( 0 \right)\left( \cfrac{\sqrt{2}}{2} \right)~~ - ~~\left( 1\right)\left( \cfrac{\sqrt{2}}{2} \right)\implies -\cfrac{\sqrt{2}}{2} \\\\[-0.35em] ~\dotfill$

$cos(67.5^o)\implies cos\left( \frac{135^o}{2} \right)\implies \pm \sqrt{\cfrac{ ~~ 1-\frac{\sqrt{2} ~~ }{2}}{2}}\implies \stackrel{I~Quadrant}{+\sqrt{\cfrac{ ~~ 1-\frac{\sqrt{2} ~~ }{2}}{2}}} \\\\\\ \sqrt{\cfrac{ ~~ \frac{2-\sqrt{2}}{2} ~~ }{2}}\implies \sqrt{\cfrac{2-\sqrt{2}}{4}}\implies \cfrac{\sqrt{2-\sqrt{2}}}{\sqrt{4}}\implies \cfrac{\sqrt{2-\sqrt{2}}}{2}$

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=16y%20%5E%7B5%7D%20-%2012y%20%5E%7B4%7D%20%2B%204y%20%5C%5C%20%5C%5C%2064%20a%20%5Ctimes%20%5E

Shkiper50 [21]

Answer:

see explanation

Step-by-step explanation:

Assuming you require to factorise the expressions

16 $y^{5}$ - 12 $y^{4}$ + 4y ← factor out 4y from each term

= 4y(4 $y^{4}$ - 3y³ + 1)

--------------------------------

64ax² - 49ay² ← factor out a from each term

= a(64x² - 49y²) ← this is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

64x² - 49y²

= (8x)² - (7y)²

= (8x - 7y)(8x + 7y)

then

64ax² - 49ay² = a(8x - 7y)(8x + 7y)

7 0

1 year ago

Please help me solve the problem

zavuch27 [327]

Answer:

f(2) = 7/4

Step-by-step explanation:

$f(x) = \frac{2x + 7 - {x}^{2} }{4} \\ f(2) = \frac{2(2) + 7 - {2}^{2} }{4} \\ f(2) = \frac{4 + 7- 4}{4} \\ f(2) = \frac{7}{4}$

3 0

3 years ago

Help a fellow dumb student

kkurt [141]

answers on on paper I did, good luck with literal equations I know they suck, just know to use inverse operations and these problems are basically normal problems replaced with variables instead.

4 0

3 years ago