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2 years ago

11

A company has two manufacturing plants with daily production levels of 7x + 19 items and 5x -2 items, respectively. The first p

lant produces how many more items daily than the second plant?

1 answer:

Gnoma [55]2 years ago

6 0

Answer:

These equations are incomplete so I cant solve it

Step-by-step explanation:

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Please help ASAP THIS IS MY FINAL QUESTION!!!! 20 points!!!!

givi [52]

Answer:

y= 1/2x-3

Step-by-step explanation:

2y - x = 8

First find the slope

2y = x+8

Divide by 2

2y/2 = x/2 +8/2

y = 1/2 x +4

The slope is 1/2 ( y=mx+b where m is the slope and b is the y intercept)

When lines are parallel they have the same slope)

Using y = mx+b

y =1/2x+b

Substituting the point (4,-1) into the equation

-1 =1/2(4)+b

-1 = 2+b

-3 =b

The equation of the line is

y= 1/2x-3

4 0

2 years ago

If 1 cm = 0.394 inches, how many inches are in 1 kilometer?

Marta_Voda [28]

Since 1 km is 100,000 cm there are 39,400 inches in a kilometer

8 0

3 years ago

Read 2 more answers

Let f(x)=5x+5 find f(-1)<br><br>I need your help with this. please help me

Alisiya [41]

$f(x) = 5x+5\\\\f(-1) = 5(-1) +5 = -5+5=0$

5 0

2 years ago

Solve for x. Show your work.<br> -1/2x < -12x

cricket20 [7]

Answer: x > 24

Step-by-step explanation: -12x/-1/2x = 24. 24 is the given when dividing. The sign is flipped after dividing negatives.

6 0

3 years ago

Read 2 more answers

Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund

lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

$\sigma=\sqrt{\frac{p*(1-p)}{n} }$

If n=1139 and p =0.96, the standard deviation is:

$\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836$

The minimum and maximum usual values are:

$\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n$

$\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62$

5 0

3 years ago