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den301095 [7]
4 years ago
5

A police car parked on the side of the highway emits a 1200 Hz sound that bounces off a vehicle farther down the highway and ret

urns with a frequency of 1250 Hz. How fast is the vehicle going?
a. 8.9
b. 6.9
c. 6.5
d. 5.6
Physics
2 answers:
Ludmilka [50]4 years ago
8 0

Answer: 1. B) 2120 Hz

2. A) 7.7 m/s

3. B) 6.9 m/s

4. C) 0.80 m; 431 Hz

5. A) 2186 Hz

6. A) the frequency of the siren is higher and the wavelength is shorter than it was at first

7. C) 300 x 10^7 m/s

8. A) 1500 Hz

9. D) 2000 Hz

10. D) 780 m/s

Explanation: 100% physics lesson 2 :)

emmasim [6.3K]4 years ago
4 0

f' = frequency observed by the police car after sound reflected from the vehicle and comes back to police car = 1250 Hz

f = frequency emitted by the police car  = 1200 Hz

V = speed of sound = 340 m/s

v = speed of vehicle = ?

frequency observed by the police car is given as

f' = f (V + v)/(V - v)

inserting the values in the above equation

1250 = 1200 (340 + v)/(340 - v)

v = 6.9 m/s

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Answer:

The ratio of the orbital time periods of A and B is \frac{1}{2}

Solution:

As per the question:

The orbit of the two satellites is circular

Also,

Orbital speed of A is 2 times the orbital speed of B

v_{oA} = 2v_{oB}        (1)

Now, we know that the orbital speed of a satellite for circular orbits is given by:

v_{o} = \farc{2\piR}{T}

where

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Now,

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v_{oA} = \farc{2\piR}{T_{a}}

Using eqn (1):

2v_{oB} = \farc{2\piR}{T_{a}}           (2)

For satellite B:

v_{oB} = \farc{2\piR}{T_{b}}              (3)

Now, comparing eqn (2) and eqn (3):

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A stone that is thrown vertically upwards was having a velocity of 15m/s after reaches 2/3 of its maximum height. What is the ma
attashe74 [19]

<em>The correct answer is option</em><em> B.</em> The maximum height that can be reached by the stone is determined as 11.5 m.

<h3>Maximum height attained by the stone </h3>

The maximum height attained by the stone when it is a 2/3 of its total height is calculated as follows;

v² = u² - 2gh

where;

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0 =  u² - 2gh

2gh =  u²

h =  u²/2g

h = (15²)/(2 x 9.8)

h = 11.48 m

h = 11.5 m

Thus, the maximum height that can be reached by the stone is determined as 11.5 m

Learn more about maximum height here: brainly.com/question/12446886

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