The time elapsed since you stopped the stopwatch is 0.41 s.
<em>Your question is not complete, it seems to be missing the following information;</em>
"The velocity of the ant is 2 m/s"
The given parameters;
- velocity of the ant, v = 2 m/s
- change in position of the ant, Δx = 0.81 m
- time when the ant was noticed, = t₂
Velocity is defined as the change in displacement per change in time of motion of an object.

The time elapsed since you stopped the stopwatch is calculated as;

Thus, the time elapsed since you stopped the stopwatch is 0.41 s.
Learn more here: brainly.com/question/18153640
The energy stored in a capacitor is
E = (1/2) · (capacitance) · (voltage)²
E = (1/2) · (6 x 10⁻⁶ F) · (12 V)²
E = (3 x 10⁻⁶ F) · (144 V²)
<em>E = 4.32 x 10⁻⁴ Joule</em>
(That's 0.000432 of a Joule)
I believe you got it correct already
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<span>The
best and most correct answer among the choices provided by the question is<span> A.
If the uncharged object is a conductor, the charged object can attract opposite
charges. </span></span>
<span><span>
</span><span>Hope my answer would be a great help for you. </span> </span>
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