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LenKa [72]
2 years ago
10

A football player kicks a ball with the force of 50N. Find the impulse on the ball if his foot stays in contact with the footbal

l for 0.01s
Physics
1 answer:
seropon [69]2 years ago
6 0

Answer:

Impulse  = 0.5Ns

Explanation:

F = 50N

t = 0.01s

Impulse = ?

Impulse = Force * t,

Impulse = 50N * 0.01s = 0.5Ns

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An proton moves with a velocity of bold v with bold rightwards harpoon with barb upwards on top equals open parentheses 5.00 spa
exis [7]

Answer:

2.64*10^-18 N

Explanation:

You have the following vectors:

\vec{v}=5.00\hat{i}-6.00\hat{j}+1.00\hat{k}\\\\\vec{B}=1.00\hat{i}+2.00\hat{j}-1.00\hat{k}

The magnitude of the magnetic force is given by the following equation:

|\vec{F_B}|=q|\vec{v}\ X\ \vec{B}|

Thus, you calculate the cross product between v and B (for example with the determinant method) and you obtain:

\vec{v}\ X\ \vec{B}=4\hat{i}-\hat{j}+16\hat{k}

Finally the magnitude of the force will be:

|\vec{F_B}|=(1.6*10^{-19}C)\sqrt{(4)^2+(-1)^2+(16)^2}N=2.64*10^{-18}N

then, the magnetic force is 2.64*10^-18 N

4 0
3 years ago
A simple model of the hydrogen atom suggests that the electron orbits the proton. What is the
andrey2020 [161]
If I remember correctly, the correct answer is either:
     A. Electrostatic
or
     B. Gravitational
7 0
3 years ago
A juggler throws balls into the air. He throws one when the previous one is at its highest point. How high the balls rise if he
VikaD [51]
<span>If "m" balls are thrown per second, the time taken for a ball to reach its maximum height will be 1/m seconds. How to get this? See that the next ball is thrown only when the previous ball reaches its maximum height. If 'm' balls were thrown in 1 second this means that each ball was attaining its maximum ht in 1/m seconds. This was the main part. Now we can proceed to find maximum height in 2 ways- a) We know for upward journey ,
t=1/m
  a=-g
  v=u-gt
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=gt = g/m
  Now we can apply h=ut-1/2 gt^2
  Putting the values of u,t, we will get h= g/2m^2
  b) The second method uses a trick that time taken to reach the maximum ht is same as time taken to fall down. So, we will now consider the downward journey of ball which also takes 1/m seconds We apply
 h=ut+1/2gt^2
Here u=0 ,t=1/m
We will again get ,
h=g/2m^2</span>
6 0
3 years ago
During a storm, the waves at this lighthouse were 5.0 meters tall top to bottom, and 10.0 m long. The waves impacted every 6.0 s
Sonbull [250]

Answer:

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Explanation:

7 0
2 years ago
What do borrowers use to secure a mortgage loan? Check all that apply.
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Answer:

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