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Alborosie
3 years ago
6

Help needeeed pls provide steppppppsssss

SAT
2 answers:
ioda3 years ago
7 0
This is the equation g of h. It means that h(g(x). Wherever there is an x input g(x).
h(g(x))= 3-(4-3x)^2
frez [133]3 years ago
5 0

(g \circ h)(x)=3-(4-3x)^2=3-(16-24x+9x^2)=3-16+24x-9x^2=-9x^2+24x-13

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in a local fitness club 32% of the members lifted weights, 41% preferred aerobics and 6%preferred both.if a member is chosen at
castortr0y [4]
<span>Members lifted weights: W=32%
</span><span>Members preferred aerobics: A=41%
</span>Members preferred both: B=6%
Members lifted weights only: Wo=W-B=32%-6%→Wo=26%
Members preferred aerobics only: Ao=A-B=41%-6%→Ao=35%
F<span>ind the probability that the member prefers another method neither weights nor aerobics to exercise: N=?

N=100%-Wo-Ao-B
N=100%-26%-35%-6%
N=100%-67%
N=33%

Answer: T</span>he probability that the member prefers another method neither weights nor aerobics to exercise is 33%
3 0
3 years ago
A 20.0-ml sample of a 0.200 mhbr solution is titrated with a 0.200 mnaoh solution. calculate the ph of the solution after the fo
kumpel [21]

The calculated pH of the solutions are given below:

  • The pH of the solution after 14.0 ml of base is added to it is calculated as 1.45.
  • The pH of the solution after 19.8 ml of base is added to it is calculated as 3.0
  • The pH of the solution after 20.0 ml of base is added to it is calculated as 7.

<h3>What is pH?</h3>

This is the level of acidity or alkalinity of an aqueous solution. The pH of a substances tells if its an acid, base or neutral.

HBr and NaOH while in water would dissociate and they would become H+ and OH- respectively.

Mol of HBr = Mol * Vol

= 0.200 * 20mL

= 4 mmol

A. Moles of NaOH added

= 0.2 X 14

= 2.8 mmol

Moles of H+ that did not react

= 4 - 2.8

= 1.2 mmol

1.2/1000 = 0.0012 moles

Total volume = 20 + 14

= 34 mL to litres

= 0.034 L

Molarity of H+ = 0.0012 / 0.034L

= 0.035 M

-log[0.035] = 1.45

The pH of the solution is  1.45

B. NaOH added = 19.8 * 0.2 =

3.96 mmoles

The unreacted solution

= 4.0 - 3.96

= 0.04 mmol

0.04/1000 = 0.00004 moles

Total volume = 20 + 19.8

= 39.8mL

Converted to litres = 0.0398L

Molarity  = 0.00004 / 0.0398L

= 0.001

-log(0.001) = 3.0

The ph Is therefore 3.0

C. Moles of NaOH added = 0.2*20mL = 4mmol

All the H+ are going to be consumed here. This would result into a neutral solution pH = 7

<u>Complete question:</u>

20.0 mL sample of 0.200 M HBr solution is titrated with 0.200 M NaOH solution. Calculate the PH of the solution after the following volumes of base have been added.

A. 14.0 mL

B. 19.8 mL

C. 20.0 mL

Read more on pH here; brainly.com/question/22390063

3 0
2 years ago
Is sat better than act for colleges?
Dvinal [7]
Most colleges dont care it all depends on your personal preference which one you want to take 
6 0
3 years ago
Read 2 more answers
Protective tariffs are considered positive because
garri49 [273]

Answer:

To shield domestic production from foreign competition by raising the price of the imported commodity

7 0
2 years ago
Can some one right the name of each moon phase in a row please.
Degger [83]

Answer:

New

Waxing Crescent

First Quarter

Waxing Gibbous

Full

Waning Gibbous

Third Quarter

Waning Crescent

Explanation:

Hope this helps!

6 0
2 years ago
Read 2 more answers
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