The minimum number of comparisons to find the smallest number from 5 integers is 4.
<h3>How to find the Smallest Integer?</h3>
Let the five numbers be a,b,c,d and e.
Let s be an integer
Comparison 1:
a and b will be compared first and the smaller number of them will be equal to s
Comparison 2:
Now, a smaller number between a and b that is s will be compared with c. Similarly, the smaller number of both numbers will be taken as s in the next comparison.
Comparison 3:
Likewise, s and d will be compared and a smaller number will be taken as s for the next comparison
Comparison 4:
Likewise, s and e will be compared and a smaller number will be taken as s for the next comparison.
After 4th comparison, s will be equal to smallest number of 5 integers.
Thus;
Total comparisons = 4
Therefore, the minimum number of comparisons to find the smallest number from 5 integers is 4.
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Answer:
It's wrong.
Explanation:
In the Punnett square, we will use F to represent the dominant freckles gene and f to represent the recessive lack-of-freckles gene. The first individual would have FF, because homozygous means that both alleles are the same. The second individual would have Ff, because heterozygous means that it has 2 different alleles. If the first individual passes down one of its "F" alleles and the second individual passes down its "F" allele, the offspring would have 2 dominant alleles, and the researcher's conclusion is disproven.
Density = mass / volume
mass = 44 g
volume = 9 cm³
Density = 44 g / 9 cm³ ≈ 4.9 ≈ 5 g/cm³
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