Answer:
c. 0.778 < p < 0.883.
Step-by-step explanation:
The formula for confidence interval for proportion =
p ± z score × √p(1 - p)/n
p = x/n
n = 195, x = 162
z score for 95% confidence Interval = 1.96
p = 162/195
p = 0.8307692308
p ≈ approximately equal to = 0.8308
0.8308 ± 1.96 × √0.8308 × (1 - 0.8308)/195
0.8308 ± 1.96 ×√0.8308 × 0.1692/195
0.8308 ± 1.96 × √0.0007208788
0.8308 ± 1.96 × 0.0268491862
0.8308 ± 0.052624405
Confidence Interval
= 0.8308 - 0.052624405
= 0.778175595
Approximately = 0.778
= 0.8308 + 0.052624405
= 0.883424405
Approximately = p
0.883
Therefore, the confidence interval for this proportion = (0.778, 0.883) or option c. 0.778 < p < 0.883
do you have a clearer picture please? I can help :))
<span>73/12 = 6 1/12
hope it helps</span>
Answer:
41/120
2/3 of 120 is 80, you have 40 left
2/5 of 40 is 16, you have 24 left
1/8 of 24 is 3.
Subtract those totals and you will get 41 leftover.
