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gavmur [86]
3 years ago
12

Which three lengths could be the lengths of the sides of a triangle?

Mathematics
2 answers:
Talja [164]3 years ago
8 0
I am assuming the answer could be C
timofeeve [1]3 years ago
4 0

Answer:  c. 8 cm, 15 cm, 22 cm

Step-by-step explanation:

  • The triangle inequality says that for any triangle, the sum of the lengths of any two sides must be greater than to the length of the remaining side.

a. 22 cm, 5 cm, 10 cm  

Here 5+10

Thus these can not be the lengths of the sides of a triangle.

b. 11 cm, 6 cm, 17 cm  

Here 6+11=17

Thus these can not be the lengths of the sides of a triangle.

c. 8 cm, 15 cm, 22 cm  

Here, 8+15>22

22+15>8\\22+8>15

Thus these three lengths can be the lengths of the sides of a triangle.

d. 6 cm, 22 cm, 10 cm

6+10

Thus these can not be the lengths of the sides of a triangle.

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josh wants to determine the number of loaves of bread he can bake using the 13 1/3 cups of flour he has
nordsb [41]

Answer:

C 4 loaves

Step-by-step explanation:

7 0
3 years ago
Rupert is copying some files from his computer to a compact disc, like the one shown above.
My name is Ann [436]

Option B: 11,304 \mathrm{mm} ^2 is the area of the compact disc.

Explanation:

The diameter of the compact disc is 120mm.

To determine the area of the compact disc, let us substitute the values in the area of the circle formula,

A=\pi r^2 where r=\frac{d}{2}

Substituting the value of d in r=\frac{d}{2}, we get,

r=\frac{120}{2} =60

Thus, r=60 and \pi=3.14. Let us substitute these values in A=\pi r^2, we get,

A=3.14\times(60)^2

Simplifying, we have,

A=3.14\times3600

Multiplying, we get,

A=11304mm^2

Thus, the area of the compact disc is 11,304 \mathrm{mm} ^2

Hence, Option B is the correct answer.

3 0
2 years ago
How to write 50,003,456 in word from
Veseljchak [2.6K]
In word form, the answer would look like this: Fifty million three thousand four hundred fifty six.
4 0
3 years ago
A web store offers two versions of a popular song. The size of a standard version is 2.9 MB. The size of the high-quality versio
olasank [31]

Answer:

This problem is a great systems of equations problem--you have two different variables: song size and number of songs.

Let's call the number of standard version downloads (S) and the high quality downloads (H).

You can make two statements:

For number of songs downloaded: S + H = 910

For download size: 2.8(S) + 4.4(H) = 3044.

S will be the same number in both equations and H will be the same number in both equations, so to find S, we can rearrange the first statement to H = 910 - S, then substitute or plug in (910 - S) wherever you see an H in the second equation so that you have only S's in your equation. Should look like this:

2.8(S) + 4.4(910 - S) = 3044

2.8S + 4004 - 4.4S = 3044

-1.6S = -960

s = 600

Your question only asks for the standard version downloads, but to help you out in future Systems situations-

You can also solve for H once you have S by plugging it into either of your equations like this:

600 + H = 910

-600

H=310

Step-by-step explanation:

hope it help

*comment if my answer is wrong*

5 0
2 years ago
What is 497,3788 * 804,4860
Vlad [161]

Answer:

40,013,428,129,680

Step-by-step explanation:

just bc

3 0
3 years ago
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