Answer:
y..............e...........s......
Use X1+X2 / 2, Y1+Y2 / 2
-3 + 2 / 2 , -5 + 7 / 2
-1 / 2 , 2/2
(-1/2, 1)
I think this is correct... I know you use the top formula
Answer:
7) 10^(3/2)
8) 2^(1/6)
9) 2^(5/4)
10) 5^(5/4)
Step-by-step explanation:
7) (√10)^3 = 10^(3/2)
8) 6 root 2 = 2^(1/6)
9) (4 root 2)^5 = 2^(5/4)
10) (4 root 5)^5 = 5^(5/4)
Hmmm I think either D or C
Answer:
3(x + 2)(2x - 5)
Step-by-step explanation:
Given
6x² - 3x - 30 ← factor out 3 from each term
= 3(2x² - x - 10) ← factor the quadratic
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 2 × - 10 = - 20 and sum = - 1
The factors are + 4 and - 5
Use these factors to split the x- term
2x² + 4x - 5x - 10 ( factor the first/second and third/fourth terms )
= 2x(x + 2) - 5(x + 2) ← factor out (x + 2) from each term
= (x + 2)(2x - 5), thus
2x² - x - 10 = (x + 2)(2x - 5) and
6x² - 3x - 30
= 3(x + 2)(2x - 5) ← in factored form
