The correct answer is A) A roast at 125°F (52°C)
Explanation:
In general terms, bacteria thrive at warm temperatures; this means bacterial growth is lower at extremely hot/cold temperatures, but it is higher at warm or medium temperatures. Indeed, the ideal temperature for bacteria to develop and reproduce is between 4° C and 60°C. This implies from the options given the roast at 52°C represents an ideal temperature for the growth of bacteria. Also, other options include temperatures above 60°C, and therefore do not allow bacteria to grow well.
by WASHING THEIR HANDS EVERY TIME THEY HANDLE FOOD OR USE THE LOUI!!!!!
One of the main differences between butter and canola oil is that are room temperature one is a solid and the other is a liquid. This change in phase is due to the bonding between carbon bonds, the more double bonds that there are present the higher the melting point and the fluidity changes. Based on this the correct answer is C=C is found in canola oil while more C-C bonds are found in butter, making option 2 (C=C) the correct answer. In addition option 3 (C=H) can be ignored since hydrogen can only make single bonds. hope this helps:)
This is a case of a patient with right sided thoracic myofascial (involving the muscles and the overlying fascia) pain involving 3 muscle groups that was injected with a local anesthetic (Bupivacaine) which are rhomboid major, rhomboid minor, and levator scapular muscles. The CPT code involving trigger point injections of 3 or more muscle groups is CPT 20553.
The arctic/polar biome
hope it helps
