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Nina [5.8K]
3 years ago
10

Solve for Y . 5(y+7)=10y A) y=7 B)y=-7 C)y=35 D)y=-35

Mathematics
2 answers:
Virty [35]3 years ago
8 0
<span>A) y = 7</span>

I hope this helps. (:
Rama09 [41]3 years ago
5 0
<span>5(y+7)=10y
Use distributive property
5y+35=10y
Subtract 5y from both sides
35=5y
Divide 5 on both sides
Final Answer: A.) 7=y</span>
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Write the equation of the line in point slope form that travels through the points (0,5) and (3,7)
Bond [772]

Answer:

y=2/3x+5

Step-by-step explanation:

to find the slope you subtract the y's from each other, and the x's from each other then put the y over the x, bam that's the slope. the y intercept is 5 cause the point is (0,5)

4 0
3 years ago
SALES A daily newspaper had 12,125 subscribers when it began publication. Five years later it had 10,100 subscribers. What is th
vekshin1

Answer:

The average change is 405

Step-by-step explanation:

The initially the number of subscriber = 12125

After five years the number of subscriber = 10100

Now we have to find the average change in the number of subscribers.

The average yearly change = change in subscriber/number of years.

Now insert the values in the above formula.

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6 0
3 years ago
Jeremy's soup is too hot to eat. He gets a cold spoon and stirs the soup
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3 years ago
Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
Tresset [83]

Answer:

Step-by-step explanation:

Hello!

Three samples of components manufactured are taken per day. They are classified as:

D: "Conforming (suitable for its use)"

E: "Downgraded (unsuitable for the intended purpose but usable for another purpose)"

F: "Scrap (not usable)"

This classification includes the three events that may occur in your sample space S. The experiment consists in recording the categories of the three parts tested in a day.

a. List the 27 outcomes in the sample space.

The possible outcomes in the space sample are the combinations of the three events. To avoid using the same letters as in the following questions I've named the evets as D, E, and F

S={DDD, DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EEE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FDD, FEE}

b. Let A be the event that all the parts fall into the same category. List the outcomes in A.

A: "All the parts fall into the same category"

You have three possible outcomes for this event, that the three compounds are conforming, "DDD", that the three are unconforming, "EEE", or that the three compounds are scrap, "FFF". There are only three possible outcomes for this event.

S={DDD, EEE, FFF}

c. Let B be the event that there is one part in each category. List the outcomes in B.

B: "There is a part in each category"

This means, for example, The first one is conforming "D", the second one is unconforming "E" and the third one is scrap "F", then the first one may be unconforming "E", the second one is conforming "D" and the thirds one is scrap "F", and so on, you have 6 possible outcomes for this event:

S={DEF, DFE, EDF, EFD, FDE, FED}

d. Let C be the event that at least two parts are conforming. List the outcomes in C.

C: "At least two parts are conforming"

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A total of 7 combinations fit this event.

I hope you have a SUPER day!

6 0
3 years ago
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lyudmila [28]

The latest sentence of proof by using the triangle congruence method we can conclude that f+e=c, a^{2} + b^{2} = c^{2}.

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So, ∠B is same in both triangles. Hence, by suing the Angle-Angle theorem rule we can conclude that both ΔABC and ΔCBD are similar.

Consequently, ∠A is same in both triangles. Hence, by suing the Angle-Angle theorem rule we can conclude that both ΔABC and ΔCBD are similar.

Similarly, When two triangles are similar then their corresponding angles are equal and their corresponding sides are also equal.

Therefore , the two proportions can be rewritten as

a² = cf ( equation 1 )

b² = ce ( equation 2 )

By adding b² on both side of equation 1 then we can write equation 1 as

a^{2} + b^{2} = b^{2}+cf

a^{2} + b^{2} = ce+cf

Because b² and ce are equal and substitute on the right side of equation 1

Using the converse of distributive property  in above equation then we get a new equation. That is,

a^{2} +b^{2}  = c(f+e)

Because distributive property is a(b+c)=a(b+ac)

a² + b² = c²

Because e + f = c²

To learn more about triangle congruency: brainly.com/question/1675117

#SPJ4

6 0
1 year ago
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