The movie theater charges $4 for children, $6 for adults, and $5 for seniors. A group of 14 people decide to go to the movies. T
1 answer:
Answer:
Adults=8
Childrens=2
Seniors=2
Step-by-step explanation:
Children $4
Adults $6
Seniors $5
There are an equal number of seniors and children.
The entire group spent a total of $66.
If 11 adults attended, the total amount will be $66 and the number of senior and childrens will be the same, 0. But this is not possible because the statement says that childrens and seniors are part of the group.
If we add the charges of childrens and seniors is equal to $9.
Assuming that the group has 2 childrens and 2 seniors the add is equal to:
Now we substract the result from the total amount:
48 is multiple of 6, this means we have in the group 8 adults, 2 childrens and 2 seniors.
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Answer:
[ 1,532.41, 1,617.59]
Step-by-step explanation:
Data provided :
Sample size, n = 120
Mean = $1,575
Standard deviation = $215
Confidence level = 97%
Now,
Confidence interval = Mean ±
also,
for 97% confidence level z score = 2.17 [from standard z-table]
= $1,575 ±
= $1,575 ± 42.59
Therefore,
Confidence interval = [ $1,575 - 42.59, $1,575 + 42.59]
= [ 1,532.41, 1,617.59]