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aalyn [17]
3 years ago
9

The movie theater charges $4 for children, $6 for adults, and $5 for seniors. A group of 14 people decide to go to the movies. T

here are an equal number of seniors and children in the group. The entire group spent a total of $66. How many ADULTS attended?
Mathematics
1 answer:
MaRussiya [10]3 years ago
4 0

Answer:

Adults=8

Childrens=2

Seniors=2

Step-by-step explanation:

Children $4

Adults $6

Seniors $5

There are an equal number of seniors and children.

The entire group spent a total of $66.

If 11 adults attended, the total amount will be $66 and the number of senior and childrens will be the same, 0. But this is not possible because the statement says that childrens and seniors are part of the group.

If we add the charges of childrens and seniors is equal to $9.

Assuming that the group has 2 childrens and 2 seniors the add is equal to:

(2*5)+(2*4)= 18

Now we substract the result from the total amount:

66-18=48

48 is multiple of 6, this means we have in the group 8 adults, 2 childrens and 2 seniors.  

         

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Answer:

7/8 > 5/6

Step-by-step explanation:

Well look at it this way: 7/8 needs 1 more eighth until 1. 5/6 needs one more sixth until one. One eighth is smaller, so it requires a smaller amount to get to a greater number, if that makes sense. So 7/8 is greater than 5/6.

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3 years ago
The graph shows y as a function of x
nirvana33 [79]
I'm guessing Q lol. I hope that's helpful.
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3 years ago
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5 0
3 years ago
Write a definite integral that represents the area of the region. (Do not evaluate the integral.)
joja [24]

Answer:

\int_{-1}^{1}7(x^{3}-x)\:dx

Step-by-step explanation:

1)  The other curve is y=0 then the common points of both curves are x-intercepts, the roots of y=7(x^{3}-x)

y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

\int_{a}^{b}|f(x)-g(x)dx

\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx

 

8 0
3 years ago
26. Use the diagram given below to answer the questions that follow. Diameter = 18cm (Use r = 3.14) a. Find the area of the circ
UkoKoshka [18]

Answer:

a. 254.34, b. 56.52

Step-by-step explanation:

a. A = πr^2,

A = 3.14(9^2)

A = 3.14*81

A = 254.34

b. C = πd

C = 18*3.14

C = 56.52

3 0
3 years ago
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