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Romashka-Z-Leto [24]
3 years ago
14

Do you think a colony on Mars should be nearer the northern or southern polar cap? Explain.

Chemistry
1 answer:
xxTIMURxx [149]3 years ago
4 0

Answer:Hola TvT

Explanation:When the Martian polar caps were first viewed through telescopes, most scientists believed that they were made of water ice, like the polar caps on Earth. Like Earth, Mars has a North and South Pole. But while Earth's polar ice caps consist solely of water ice, Mars' polar caps are a combination of water ice and carbon dioxide ice. As the Martian seasons change, the carbon dioxide ice sublimates (vaporizes) in summer, revealing the surface, and freezes again in winter. As fall approaches, in each respective hemisphere, clouds begin to form over the polar region and the ice cap begins to grow. In spring, the polar caps recede...........Aside from ice, Mars' polar regions have some interesting geologic features. The north polar dune field is a vast concentration of sand dunes that stretches around the entire north polar cap. In some areas, the sand measures up to 500 km (300 miles) across. When the dunes begin to thaw in spring, dark spots form on their surfaces. The north polar dunes were first seen during the 1972 mapping of Mars by Mariner 9, and they are identical to dunes in Earth's desert regions..

bye bye UnU

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What is the percentage of the actual yield of the reaction of 2.5 mol of Fe(NO3),
Sliva [168]

Answer:

Percent yield = 87.5%

Explanation:

Given data:

Number of moles of Fe(NO₃)₃ = 2.5 mol

Number of moles of Na₂CO₃ = 3.6 mol

Actual yield of NaNO₃ = 6.3 mol

Percent yield of NaNO₃ = ?

Solution:

Chemical equation:

2Fe(NO₃)₃ + 3Na₂CO₃        →     Fe₂(CO₃)₃ + 6NaNO₃

now we will compare the moles of both reactant with NaNO₃.

                   Fe(NO₃)₃          :              NaNO₃

                       2                   :                  6

                     2.5                  :            6/2×2.5 = 7.5

                  Na₂CO₃             :              NaNO₃

                       3                   :                  6

                     3.6                  :            6/3×3.6 = 7.2

Theoretical yield of NaNO₃ is 7.2 mol.

Percent yield:

Percent yield = actual yield / theoretical yield ×100

Percent yield = 6.3 mol / 7.2mol ×100

Percent yield = 87.5%

5 0
3 years ago
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A chemistry student must write down in her lab notebook the concentration of a solution of sodium hydroxide. The concentration o
taurus [48]

Answer:

The concentration the student should write down in her lab is 2.2 mol/L

Explanation:

Atomic mass of the elements are:

Na: 22.989 u

S: 32.065 u

O: 15.999 u

Molar mass of sodium thiosulfate, Na2S2O3 = (2*22.989 + 2*32.065 + 3*15.999) g/mol = 158.105 g/mol.

Mass of Na2S2O3 taken = (19.440 - 2.2) g = 17.240 g.

For mole(s) of Na2S2O3 = (mass taken)/(molar mass)

= (17.240 g)/(158.105 g/mol) = 0.1090 mole.

Volume of the solution = 50.29 mL = (50.29 mL)*(1 L)/(1000 mL)

= 0.05029 L.

To find the molar concentration of the sodium thiosulfate solution prepared we use the formula:

= (moles of sodium thiosulfate)/(volume of solution in L)

= (0.1090 mole)/(0.05029 L)

= 2.1674 mol/L

6 0
3 years ago
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