I would have to say cholesterol
Answer:
Percent yield = 87.5%
Explanation:
Given data:
Number of moles of Fe(NO₃)₃ = 2.5 mol
Number of moles of Na₂CO₃ = 3.6 mol
Actual yield of NaNO₃ = 6.3 mol
Percent yield of NaNO₃ = ?
Solution:
Chemical equation:
2Fe(NO₃)₃ + 3Na₂CO₃ → Fe₂(CO₃)₃ + 6NaNO₃
now we will compare the moles of both reactant with NaNO₃.
Fe(NO₃)₃ : NaNO₃
2 : 6
2.5 : 6/2×2.5 = 7.5
Na₂CO₃ : NaNO₃
3 : 6
3.6 : 6/3×3.6 = 7.2
Theoretical yield of NaNO₃ is 7.2 mol.
Percent yield:
Percent yield = actual yield / theoretical yield ×100
Percent yield = 6.3 mol / 7.2mol ×100
Percent yield = 87.5%
Gemini VII was the first successful docking
Answer:
The concentration the student should write down in her lab is 2.2 mol/L
Explanation:
Atomic mass of the elements are:
Na: 22.989 u
S: 32.065 u
O: 15.999 u
Molar mass of sodium thiosulfate, Na2S2O3 = (2*22.989 + 2*32.065 + 3*15.999) g/mol = 158.105 g/mol.
Mass of Na2S2O3 taken = (19.440 - 2.2) g = 17.240 g.
For mole(s) of Na2S2O3 = (mass taken)/(molar mass)
= (17.240 g)/(158.105 g/mol) = 0.1090 mole.
Volume of the solution = 50.29 mL = (50.29 mL)*(1 L)/(1000 mL)
= 0.05029 L.
To find the molar concentration of the sodium thiosulfate solution prepared we use the formula:
= (moles of sodium thiosulfate)/(volume of solution in L)
= (0.1090 mole)/(0.05029 L)
= 2.1674 mol/L