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DIA [1.3K]
3 years ago
10

Why was the royal society of london formed

Chemistry
1 answer:
bazaltina [42]3 years ago
3 0

Answer:

..............what.......

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Consider the following intermediate chemical equations.
mixas84 [53]

Answer:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l).

Explanation:

  • We have two equations:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

2H₂O(g) → 2H₂O(l)

  • To add the two equations: we omit H₂O(g)  that is formed by 2 moles in the product side of the first equation and consumed by 2 moles from the reactants side in the second equation

  • So, the overall chemical equation is obtained by combining these intermediate equations is:

<em>CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l).</em>

<em></em>

8 0
3 years ago
Read 2 more answers
Can multiple people use one brainly account at the same time on a computer??
viva [34]

Answer:

No

Explanation:

...............................

3 0
3 years ago
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Calculate the ph of a solution prepared by dilution 3.0 ml of 2.5 m hcl to a final volume of 100 ml with h2o.
dexar [7]

The pH of the solution after dilution is 1.125.

HCl is hydrochloric acid. It is known by the name muriatic acid. It is among the strong acids. It has a pungent smell and is colorless. It has a molar mass of 36.4 g/mol. It's a common reagent used in pharmaceutical industries. It is also used in other industries such as textile, rubber, and metal.

The volume of HCl added to the solution = 3.0 ml

The molar concentration of HCl = 2.5 M

Let the molar concentration of the solution after dilution is x.

The volume of the diluted solution = 100 ml.

The molar concentration of the solution after dilution is,

M _{1} V _{2} = M_{2} V _{2}

M_{2} =   \frac{ M _{1} V _{2}}{V _{2} }

M_{2} =  \frac{2.5 \times 3}{100}

= 0.075 \: M

Thus, the molar concentration of the solution after dilution is 0.075 M.

The pH of the solution after the dilution is,

[HCl] = [H ^{ + } ]  = 0.075 \: M

pH =  - log [H ^{ + } ]

pH = -  log(0.075)

pH = 1.125

Therefore, the pH of the solution after dilution is 1.125.

To know more about hydrochloric acid, refer to the below link:

brainly.com/question/3637432

#SPJ4

3 0
2 years ago
In NMR if a chemical shift(δ) is 211.5 ppm from the tetramethylsilane (TMS) standard and the spectrometer frequency is 556 MHz,
Vika [28.1K]

Answer:

The answer is: 11759 Hz

Explanation:

Given: Chemical shift: δ = 211.5 ppm, Spectrometer frequency = 556 MHz = 556 × 10⁶ Hz

In NMR spectroscopy, the chemical shift (δ), expressed in ppm, of a given nucleus is given by the equation:

\delta (ppm) = \frac{Observed\,frequency (Hz)}{Frequency\,\, of\,\,the\,Spectrometer (MHz)} \times 10^{6}

\therefore Observed\,frequency (Hz)= \frac{\delta (ppm)\times Frequency\,\, of\,\,the\,Spectrometer (MHz)}{10^{6}}

Observed\,frequency= \frac{211.5 ppm \times 556 \times 10^{6} Hz}{10^{6}} = 11759 Hz

<u>Therefore, the signal is at 11759 Hz from the TMS.</u>

6 0
4 years ago
It _______ moving right now.
Arte-miy333 [17]

Answer:

Umm what do i do to help you??

7 0
3 years ago
Read 2 more answers
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