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2 years ago

Consider the following quadratic function. (Graph) What is the value of a?

Mathematics

1 answer:

balu736 [363]2 years ago

5 0

I believe that the a value is 2

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Answer: Its A Im pretty sure

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3 years ago

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Jessica spent 2/5 of her money going to the movies. Then she babysat her brother and earned fifteen more dollars. If she ended u

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2 years ago

Rich measured the height of a desk to be 80.7 cm. The actual height of the desk is 80 cm. What is Rich's percent error in this c

Hitman42 [59]

Answer:

0.9%

Step-by-step explanation:

We have been given that Rich measured the height of a desk to be 80.7 cm. The actual height of the desk is 80 cm.

We will use percentage error formula to solve our given problem.

$\text{Percentage error}=\frac{\text{Experimental value-Actual value }}{\text{Actual actual}}\times 100$

$\text{Percentage error}=\frac{80.7-80}{80}\times 100$

$\text{Percentage error}=\frac{0.7}{80}\times 100$

$\text{Percentage error}=0.00875\times 100$

$\text{Percentage error}=0.875\approx 0.9$

Therefore, Rich's percent error in calculation is 0.9%.

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3 years ago

How do you know if x is on the rhs or the lhs?

olga nikolaevna [1]

Answer:

Step-by-step explanation:

RHS means on the right hand side

And LHS means on the left hand side

So if x is one the right side of the expression ,it is on the RHS and if it is on the left side of the expression , it is on the LHS

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2 years ago

For what value of constant c is the function k(x) continuous at x = 0 if k =

nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:

$\mathbf{ \lim_{x \to 0^-} k(x) = \lim_{x \to 0^+} k(x) = 0 }$

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= c }$

Provided that:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }$

Using l'Hospital's rule:

$\mathbf{\implies \lim_{x \to 0} \ \ \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}= \lim_{x \to 0} sec \ x \ tan \ x = 0}$

Therefore:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}=0 }$

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

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1 year ago