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lara31 [8.8K]
3 years ago
6

Consider the following quadratic function. (Graph) What is the value of a?

Mathematics
1 answer:
balu736 [363]3 years ago
5 0
I believe that the a value is 2

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The possible outcomes for tossing a coin four times are shown below.
stich3 [128]
Hello,

TTTT=>(1/2)^4=1/16
=================

3 0
3 years ago
Read 2 more answers
The table and the graph below each show a different relationship between the same two variables, x and y:
olga2289 [7]

The value of y will be 60 so the correct answer is option C.

<h3>What is a graph?</h3>

A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.

There is a linear relationship between the two variables x and y. For the given data in the table as well as in the graph. The expression for the two variables will be written in the form of an equation as follows:-

The expression for the data in the table:-

y = 25 x now at x = 12

y = 25 x 12 = 300

The expression for the values in the graph:-

y  = 30x at x = 12

y  = 30 x 12

Y = 360

How much more would the value of y be on the graph will be calculated as:-

Value  = 360 - 300

Value = 60

Therefore the value of y will be 60 so the correct answer is option C.

To know more about graphs follow

brainly.com/question/25020119

#SPJ1

5 0
2 years ago
A chain lying on the ground is 10 m long and its mass is 70 kg. How much work (in J) is required to raise one end of the chain t
DerKrebs [107]

Answer:

W= 34.3 \frac{kg}{s^2} (4^2-0^2)m^2 =548.8 \frac{kg m^2}{s^2} =548.8 J

Step-by-step explanation:

Data Given: m = 70 kg , g = 9.8 ms^-2, h =10m.

For this case we can use the following formula:

W = \int_{x_i}^{x_f} F(x) dx

For this case we need to find an expression for the force in terms of the distance. And since on this case the total distance is 10 m long we can write the expression like this:

F(x) = \frac{ma}{10m}= \frac{mg}{10m} x

The only acceleration on this case is the gravity and if we replace the values given we got:

\frac{70 kg *9.8 m/s^2}{10m} x=68.6 x\frac{kg}{s^2}

Now we can find the required work with the following integral:

W= 68.6 \frac{kg}{s^2} \int_{0}^4 x dx

W= 34.3 \frac{kg}{s^2} x^2 \Big|_0^4

W= 34.3 \frac{kg}{s^2} (4^2-0^2)m^2 =548.8 \frac{kg m^2}{s^2} =548.8 J

7 0
4 years ago
Can somebody help me/tell me how to do these?
andreyandreev [35.5K]

Hi! I'll try to help

It gives you two equations, one for "x" and one for "y"

All you have to do is replace the variable "y" with its value in the second equation. Might be kind of confusing so let's do one.

y=4x

3x-y=1

Since we know that "y" is the same as 4x, you can rewrite the equation as

3x-4x=1

Next, all you have to do is combine like terms as solve "3x-4x" which is -x

Let's rewrite the equation, then:

-x=1

You can simplify it to

x=-1

by dividing both sides by negative one, in other words swapping the negative sign so that "x" is positive

7 0
2 years ago
A rectangle is 15m longer than it is wide. Its perimeter is 72m. Find its length and width.
Dahasolnce [82]
L 6 w 8 is the right answer to the question
6 0
2 years ago
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