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2 answers:
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Answer:
Null hypothesis:
Alternative hypothesis:
When we talk about a type I of error we are refering to a“false positive” and is associated when we reject a null hypothesis when it is actually true.
And for this special case would be reject the null hypothesis that the true mean is lower or equal than 300 [/tex]\mu\leq 300[/tex] but that in fact is true.
This type of error is associated to the significance level assumed for the statistical test
Step-by-step explanation:
For this case we define the random variable X as the number of automobiles pass at a location per hour and we are tryng to proof this:
Null hypothesis:
Alternative hypothesis:
When we talk about a type I of error we are refering to a“false positive” and is associated when we reject a null hypothesis when it is actually true.
And for this special case would be reject the null hypothesis that the true mean is lower or equal than 300 [/tex]\mu\leq 300[/tex] but that in fact is true.
This type of error is associated to the significance level assumed for the statistical test
Answer:
4. y = 2x -6
5. y = -x + 3
6. y = -x - 1
7. m= -4 and b=3
8. m= 1 and b=-7
9. y = 0.08x + 3
10. y= 3x - 19
11. y= -3x + 5
Step-by-step explanation:
Use the equation y = mx + b; where m is the slope and b is the y-intercept
4. given: m = 2 and y-int = -6; plug into equation
y = mx + b
y = 2x -6
5. given: m = -1 and y-int = 3; plug into equation
y = mx + b
y = -x + 3
6. given: m = -1/3 and y-int = -1; plug into equation
y = mx + b
y = -x - 1
7. given: y=-4x+3; slope m and y-intercept b are
m= -4
b=3
8. given: y=x-7; slope m and y-intercept b are
m= 1
b=-7
9. the monthly of $3 is fixed or starts the month; which is the y-intercept (another way to say is it is at 0 minutes) so b = 3. Now the rate is $0.08 per minutes and the rate is the same as the slope, m= 0.08
Using equation y=mx+b; substitute
y = 0.08x + 3
10. Given: (6,-1) and m= 3
use y=mx+b; substitute the y point into equation
-1 = 3x + b; substitue the x point into equation
-1 = 3(6) + b; solve for b
b = -19; now plug back into equation
y = mx + b or y= 3x - 19
11. Given: (2,-1) and m= -3
use y=mx+b; substitute the y point into equation
-1 = -3x + b; substitue the x point into equation
-1 = -3(2) + b; solve for b
b = 5; now plug back into equation
y = mx + b or y= -3x + 5