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nalin [4]
3 years ago
9

At the point of fission, a nucleus of 235U that has 92 protons is divided into two smaller spheres, each of which has 46 protons

and a radius of 5.9 × 10−15 m. What is the magnitude of the repulsive force pushing these two spheres apart? The value of the Coulomb constant is 8.98755 × 109 N · m2 /C 2 .

Physics
1 answer:
Gwar [14]3 years ago
7 0

Answer:

Force = 3481.1 N.

Explanation:

Below is an attachment containing the solution.

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Light from an argon laser strikes a diffraction grating that has 4,917 lines per cm. The first-order principal maxima are separa
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Answer:

Wavelength is 4.8x10^-7m

Explanation:

See attached file

3 0
3 years ago
If a plane has an airspeed of 40 m/s and is experiencing a crosswind of 30 m/s, what is its ground speed in m/s?
Anon25 [30]
<h2>Answer:50ms^{-1}</h2>

Explanation:

Let v_{a} be the airspeed.

Let v_{w} be the cross wind speed.

We know that,ground speed is the vector sum of airspeed and cross wind speed and airspeed is perpendicular to cross wind speed.

If v_{1} and v_{2} are two perpendicular vectors,the resultant vector has the magnitude \sqrt{|v|_{1}^{2}+|v|_{2}^{2}}

Given,

v_{a}=40ms^{-1}\\v_{c}=30ms^{-1}

So,the ground speed is \sqrt{40^{2}+30^{2}}=\sqrt{2500}=50ms^{-1}

6 0
3 years ago
the batter swings the bat and makes contact with the ball. when this occurs, the kinetic energy of the bat is transferred to the
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It will possibly be A) chemical b/c it can make a sound like when the bar hits the ball it makes a sound correct?! and also it created heat especially when it hits the ball. and when the ball MOVES and the bar HITS it creates kinetic energy, but when you hit the ball it doesn’t create a new substance.
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What force is produced when a battery causes an electric current to flow trough a circuit made of copper wire
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You'll hear that force called different things in different places. It
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It's just a matter of somehow causing the two ends of the wire
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7 0
4 years ago
A typical running track is an oval with 74-m-diameter half circles at each end. A runner going once around the track covers a di
nirvana33 [79]

Answer:

The acceleration towards the center will be 0.43\ m/s^2

Explanation:

Given the running track is an oval shape, and the diameter of each half-circle is 74 meters.

Also, the runner took 1 minute and 40 seconds to complete 400 m one round of the track.

We need to find the acceleration towards the center.

First, we will find the speed.

v=\frac{d}{t}

Where v is the speed.

d is the distance covered by the rider that is 400 meters.

t is the time taken by the rider to complete the lap which is 1 minute and 40 seconds.  (60\ s +40\ s) = 100 seconds.

So,

v=\frac{400}{100}=4\ m/s

And

a_c=\frac{v^2}{r}

Where a_c is the acceleration towards the center.

r is the radius which will be the half of the diameter 74 meters.

Hence, the radius will be 37 meters.

a_c=\frac{4^2}{37} \\a_c=\frac{16}{37}=0.43\ m/s^2

So, the centripetal acceleration of the rider will be 0.43\ m/s^2

4 0
3 years ago
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