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Daniel [21]
4 years ago
9

Figure 9.27

Physics
1 answer:
liraira [26]4 years ago
3 0
Hcchhchchhhchchchcnjnnnnnn
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Which of the following is an example of an immiscible liquid?
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I place an ice cube with a mass of 0.223 kg and a temperature of −35◦C is placed into an insulated aluminum container with a mas
Nadya [2.5K]

To solve this problem it is necessary to use the calorimetry principle. From the statement it asks about the remaining ice, that is, to the point where the final temperature is 0 ° C.

We will calculate the melted ice and in the end we will subtract the total initial mass to find out how much mass was left.

The amount of heat transferred is defined by

Q = mc\Delta T

Where,

m = mass

c = Specific heat

\Delta T =Change in temperature

There are two states, the first is that of heat absorbed by that mass 'm' of melted ice and the second is that of heat absorbed by heat from -35 ° C until 0 ° C is reached.

Performing energy balance then we will have to

Q_i-E_h = Q_m

Where,

Q_ i= Heat absorbed by whole ice

Q_m= Heat absorbed by mass

E_h= Heat energy by latent heat fusion/melting

m_i*c_i \Delta T +m*L_f  = (m_wc_w+m_{al}c_{al})\Delta T

Replacing with our values we have that

0.223*2108(-(-35))+m*3.34*10^5 = (0.452*4186+0.553*902)(27-0)

16452.9+334000m = (1892.072+498.806)*27

Rearrange and find m,

m = 0.144Kg

Therefore the Ice left would be

m' = 0.223-0.144

m' = 0.079Kg

Therefore there is 0.079kg ice in the containter when it reaches equilibrium

8 0
4 years ago
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