A quantum of electromagnetic radiation has an energy of 2.0 kev. what is its frequency? planck's constant is 6.63 × 10−34 j · s.
1 answer:
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Answer:
2a) x = 32 [mil/h]; 2b) t = 0.5[h]; 3a) t = 2.5 [h]; 3b) x = 185[mil]
Explanation:
2a)
We can solve this problem by using the kinematics equation, which relates speed to time and displacement.
2b)
We can solve this problem by using the kinematics equation, which relates speed to time and displacement.
3a)
We can solve this problem by using the kinematics equation, which relates speed to time and displacement.
3b)
We can solve this problem by using the kinematics equation, which relates speed to time and displacement.
The Image distance and Magnification of The Image will be 30 cm and 3.
<h3>What is focal length?</h3>The focal length of the lens, which is often expressed in millimeters, is the distance between the lens and the image sensor when the subject is in focus.
Given data;
Focal length,f=?
Image distance,v=?
Object distance,u= 10 cm
Magnification,m= 2.85
The focal length is half of the radius;
f=R/2
f=30 Cm/2
f= 15 Cm
The mirror equation is found as;
The magnification of the lens is found as;
Hence, the image distance and magnification of The image will be 30 cm and 3.
To learn more about the focal length refer;
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