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Firlakuza [10]
3 years ago
5

Stuck, need help please.

Mathematics
1 answer:
Maurinko [17]3 years ago
7 0

Answer:

22.5 lbs

Step-by-step explanation:

First you find the cubic feet. That is the volume of the object which is length*width*height.

In your example, they are using inches. So you have to convert all units to feet. That would be 0.5 inches, 0.5 inches, and 5/3 inches. The volume would be 0.5*0.5*5/3 which is about 5/12 cubic feet

You then take that 5/12 cubic feet and multiply it by the 54 lbs/cubic foot. The answer would be 22.5 lbs

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Need help regarding radioactive decay type of question
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By applying the <em>radioactive simple decay</em> model, we find that the <em>initial</em> quantity of the <em>radioactive</em> isotope is equal to approximately 5.63 grams.

<h3>How to determine the initial mass of a radioactive isotope</h3>

Mass of <em>radioactive</em> isotopes (m (t)), in grams, decay exponentially in time according to the following model:

m(t) = m_{o}\cdot e^{-t/\tau}     (1)

Where:

  • m_{o} - Initial mass, in grams
  • t - Time, in years
  • τ - Time constant, in years

The <em>time</em> constant can be found in terms of half-life:

τ = t'/㏑ 2

If we know that t' = 24100 yr, t = 1000 yr and m(t) = 5.4 g, then the initial mass of the <em>radioactive</em> isotope is:

τ = 24100 yr/㏑ 2

τ ≈ 34768.95 yr

5.4 = m_{o}\cdot e^{-1000/24100}

m_{o} = 5.629\,g

By applying the <em>radioactive simple decay</em> model, we find that the <em>initial</em> quantity of the <em>radioactive</em> isotope is equal to approximately 5.63 grams.

To learn more on radioactive decay: brainly.com/question/1770619

#SPJ1

8 0
2 years ago
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