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Ipatiy [6.2K]
3 years ago
12

What is the main type of heat transfer.

Chemistry
1 answer:
krek1111 [17]3 years ago
8 0

Conduction

Convection

Radiation

Explanation:

The main types of heat transfer are heat transfer by conduction, convection and by radiation.

These forms of heat transfer has different modes of application.

  • Conduction is a form of heat transfer in solids. It requires a material medium to dissipate. Here, heat flows from a hot end to a cold end.
  • Convection is a form of heat transfer in fluids i.e liquids and gases. In convection, heat is transferred due to density differences between heated fluids.
  • Radiation does not involve material medium. It uses the electromagnetic waves to dissipate heat.

learn more:

Conduction brainly.com/question/1140127

#learnwithBrainly

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What do the little numbers (subscripts) next to the lower right of each letter mean in the C₂H₄O₂?
nata0808 [166]

Answer:

It represents the <em>number of atoms</em> of that particular element present in the compound. In C₂H₄O₂ there are 2 Carbon atoms, 4 Hydrogen atoms and 2 Oxygen atoms.

3 0
2 years ago
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5 0
3 years ago
Find the rms speed of the molecules of a sample of n2 (diatomic nitrogen) gas at a temperature of 32.5°c.
Korvikt [17]
The rms speed of a gas can be calculated using the following rule:
Vrms = sqrt[(3RT) / M] where
R is the gas constant = 8.314 <span>J K^−1 mol^−1
T is the temperature = 32.5 + 273 = 305.5 degree kelvin
M is the molar mass = 2*14 = 28 grams = 0.028 kg

Substitute with the givens in the equation to get the rms speed as follows:
Vrms = sqrt [(3*8.314*305.5) / 0.028]
Vrms = 521.665 m/sec</span>
5 0
4 years ago
Cyanogen is a gas which contains 46.2% C and 53.8% N by mass. At a temperature of 25°C and a pressure of 750 mm Hg, 1.50 g of cy
sergiy2304 [10]

Answer:

Molecular formula of cyanogen is C₂N₂

Explanation:

We apply the ideal gases law to find out the mole of cyanogen

P . V =  n. R. T

Firstly let's convert the pressure in atm, for R

750 mmHg = 0.986 atm

25°C + 273 = 298K

0.986 atm . 0.714L = n . 0.082 L.atm/mol.K .298K

(0.986 atm . 0.714L) / (0.082 L.atm/mol.K .298K) = n

0.0288 mol = n

Molar mass of cyanogen = mass / mol

1.50 g /0.0288 mol = 52.02 g/m

Let's apply the percent, to know the quantity of atoms

100 g of compound contain 46.2 g of C and 53.8 g of N

52.02 g of compound contain:

(52.02 . 46.2) / 100 = 24 g  → 2 atoms of C

(52.02 . 53.8) / 100 = .28 g  →  2 atoms of N

3 0
3 years ago
sodium tends to lose a single electron in natural settings based on what you know what are two other elements that tend to do th
fomenos
<span>Potassium and rubidium as they are in the same periodic table group as Na</span>
3 0
4 years ago
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