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Scilla [17]
4 years ago
11

Suppose you have a solution that might contain or all of the following cations: Cu2+, Ag+, Ba2+, and Mn2+. Addition of HBr cause

s a precipitate to form. After the precipitate is filtered off, H2SO4 is added to the supernate another precipitate forms. This precipitate is filtered off, and a solution of NaOH is added to the supernatant liquid until it is strongly alkaline. No precipitate is formed. Which ions are present in each of the precipitates? Which cations are not present in the original solution?
Chemistry
2 answers:
Aneli [31]4 years ago
8 0
Bat2 is the cations for your question
timofeeve [1]4 years ago
3 0

Answer:

Both Ba2+ and Ag+ are present.

Neither Cu2+ nor Mn^2+ are present.

Explanation:

Hello,

At first, the addition of HBr promotes the precipitation of AgBr as it is largely insoluble in water. Next, the addition of H2SO4 promotes the precipitation of BaSO4 as it is largely insoluble in water as well.

Finally, as no precipitate was formed due to the addition of sodium hydroxide and both Cu(OH)2 and Mn(OH)2, one concludes they aren't present into the solution.

Best regards.

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he first solution contains 25 % acid, the second contains 35 % acid, and the third contains 55 % acid. She created 100 liters of
photoshop1234 [79]

Answer:

Volume of first solution       =  20 Liters

Volume of second solution =  20 Liters

Volume of third solution     =  60 Liters

Explanation:

Let the volume second solution  used= y

Let the volume of third solution used = 3y

Let the volume of first solution used = 100 - (y +3y)

                                                             = 100- 4y

The volume of acid in the first solution ( V₁)  = 25% of (100-4y)

                                                                         = 25-y

The volume of acid in the second solution(V₂)  =35% of y

                                                                              = 0.35y

The volume  acid in the  third solution (V₃)  = 55% of 3y

                                                                       =1.65y

The  Volume of acid in Mixture (V₄)   =   45% of 100

                                                             =  45

From the conservation of volume:

V₄ =  V₁  +  V₂ + V₃

45 = (25-y )+ 0.35y + 1.65y

45 =25 -y + 0.35y + 1.65y

45 -25 = y

y = 20

So the volume of first solution used = 100- 4y

                                                             = 100- 4(20)

                                                             =  20 Liters

So the volume of second solution used = y

                                                             =  20 Liters

So the volume of third solution used = 3y

                                                             =  3(20)

                                                             =  60 Liters

3 0
3 years ago
How many grams of H20 will be produced by 18g H2
AURORKA [14]

Answer:

160.86 g to the nearest hundredth.

Explanation:

H2 + O  ---> H2O

2.016 g H2 produces 18.016 g H2O

1g      ..    ..   ..   ..   ..    18.016 / 2.016 g H2O

18g   ..   ..   ..  ..  .. . .     (18.016 * 18) / 2.016 g H2O.

= 160.86 g.

8 0
3 years ago
A student finds two unlabeled flasks of clear liquids. One is believed to be 0.1 m nacl and the other to be 0.1 m naclo3. What i
KonstantinChe [14]

Answer:

  • Add AgNO₃ solution to both unlabeled flasks: based on solubility rules, you can predict that when you add AgNO₃ to the NaCl solution, you will obtain AgCl precipitate, while no precipitate will be formed from the NaClO₃ solution.

Explanation:

<u>1. Adding AgNO₃ to NaCl solution:</u>

  • AgNO₃ (aq) + NaCl (aq) → AgCl (s) + NaNO₃ (aq)

<u>2. Adding AgNO₃ to NaClO₃ solution</u>

  • AgNO₃ (aq) + NaClO₃ (aq) → AgClO₃ (aq) + NaNO₃ (aq)

<u />

<u>3. Relevant solubility rules for the problem.</u>

  • Although most salts containing Cl⁻ are soluble, AgCl is a remarkable exception and is insoluble.

  • All chlorates are soluble, so AgClO₃ is soluble.

  • Salts containing nitrate ion (NO₃⁻) are generally soluble and NaNO₃ is not an exception to this rule. In fact, NaNO₃ is very well known to be soluble.

Hence, when you add AgNO₃ to the NaCl solution the AgCl formed will precipitate, and when you add the same salt (AgNO₃) to the AgClO₃ solution both formed salts AgClO₃ and NaNO₃ are soluble.

Then, the precipiate will permit to conclude which flask contains AgCl.

6 0
3 years ago
Calvert likes to paddle around in his canoe. One day it sprung a leak and started to fill with water. Luckily, Calvert was able
allochka39001 [22]
The hole in the boat caused it to take on water, as the boat filled with water, it became less and less buoyant, eventually filling with water until losing buoyancy completely and sinking.
5 0
3 years ago
What is the pH of 1 x 10 M HCl solution?​
notka56 [123]

Answer:

 

less than zero

Explanation:

5 0
3 years ago
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