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jek_recluse [69]
3 years ago
8

A lab technician needs to create 570.0 milliliters of a 2.00 M solution of magnesium chloride (MgCl2). To make this solution, ho

w many grams of magnesium chloride does the technician need?
Chemistry
2 answers:
vekshin13 years ago
7 0

Hey there!:

Molar mass MgCl2 = 95.211 g/mol

Volume of solution in liters:

570.0 mL / 1000 => 0.57 L

Number of moles:

n = M * V

n = 2.00 * 0.57 => 1.14 moles of MgCl2

Therefore:

1 mol MgCl2 --------------- 95.211 g

1.14 moles MgCl2 ---------- ??

mass of MgCl2 = 1.14 * 95.211

mass of MgCl2 = 108.54 g


Hope that helps!

Nataly_w [17]3 years ago
6 0

109 for brainly just did it 5/5 correct (Three significant figures)

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The reaction 2NO(g)+O2(g)−→−2NO2(g) is second order in NO and first order in O2. When [NO]=0.040M, and [O2]=0.035M, the observed
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Answer:

(a) The rate of disappearance of O_{2} is: 4.65*10^{-5} M/s

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(c) The units of rate constant is:  M^{-2}s^{-1}

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The rate of a reaction can be expressed in terms of the concentrations of the reactants and products in accordance with the balanced equation.

For the given reaction:

2NO(g)+O_{2}->2NO_{2}

rate = -\frac{1}{2} \frac{d}{dt}[NO] = -\frac{d}{dt}[O_{2}] = \frac{1}{2}\frac{d}{dt}[NO_{2}] -----(1)

According to the question, the reaction is second order in NO and first order in  O_{2}.

Then we can say that, rate = k[NO]^{2}[O_{2}] -----(2)

where k is the rate constant.

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(b) The rate of the reaction can be obtained from (1).

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    rate = 4.65*10^{-5} M/s

   The value of rate constant can be obtained by using (2).

    rate constant = k = \frac{rate}{[NO]^{2}[O_{2}]}

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(c) The units of the rate constant can be obtained from (2).

    k = \frac{rate}{[NO]^{2}[O_{2}]}

    Substituting the units of rate as M/s and concentrations as M, we get:

\frac{Ms^{-1} }{M^{3}} = M^{-2}s^{-1}

(d) The reaction is second order in NO. Rate is proportional to square of the concentration of NO.

     rate\alpha [NO]^{2}

If the concentration of NO increases by a factor of 1.8, the rate will increase by a factor of (1.8)^{2} = 3.24

     

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