Here we have to write a simple equation which describes the action of the enzyme catalase.
The equation is: The concentration of the complex [ES] =
Let us consider an enzyme catalyses reaction E + S ⇄ ES → E + P
Where E, S, ES and P are enzyme, substrate, complex and product respectively.
The concentration of the complex [ES] = , where is the Michaelis constant.
[E]₀ and [S] is the initial concentration of enzyme and concentration of substrate respectively.
Answer: must have THE SAME number of atoms for each element
Explanation: Chemical equations must be balanced -- they must have the same number of atoms of each element on both sides of the equation. As a result, the mass of the reactants must be equal to the mass of the products of the reaction.
I’m pretty sure you add, multiply, subtract, & divide
Remembering that
d = m ÷ v
d = ?
m = 89 g
v = 10 cm³
Therefore:
d = 89 ÷ 10
d = 8,9 g÷cm³
Answer:
21.5 g.
Explanation:
Hello!
In this case, since the reaction between the given compounds is:
We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:
Now, the moles of Li3P consumed by 15 g of Al2O3:
Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:
Therefore, the total mass of products is:
Which is not the same to the reactants (53 g) because there is an excess of Li₃P.
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