Question

Pls Help!!! Worth 99 Pts!!

Answer 1

First, for end behavior, the highest power of x is x^3 and it is positive. So towards infinity, the graph will be positive, and towards negative infinity the graph will be negative (because this is a cubic graph)

To find the zeros, you set the equation equal to 0 and solve for x
x^3+2x^2-8x=0
x(x^2+2x-8)=0
x(x+4)(x-2)=0
x=0   x=-4   x=2

So the zeros are at 0, -4, and 2. Therefore, you can plot the points (0,0), (-4,0) and (2,0)

And we can plug values into the original that are between each of the zeros to see which intervals are positive or negative.
Plugging in a -5 gets us -35
-1 gets us 9
1 gets us -5 
3 gets us 21

So now you know end behavior, zeroes, and signs of intervals

Hope this helps<span />

Answer 2

I hope this helps you



f (x)=x. (x^2+2x-8)



f (x)=x. (x+4)(x-2)



x=0


x= -4



x= 2