The quadratic formula is =(-b+-sqrt(b^2-4ac))/2a
as you notice the term under the square root is b^2-4ac if it is postive then the equation clearly will have two real soultions if it is negative then the equation will have two imaginary soultion if it is zero then the the equation will have one soultion
so let us calculate b^2-4ac for our given equation
x^2=4x-5 so let us write it in general form which is ax^2+bx+c=0
subtracting 4x from both sides
x^2-4x=-5
adding 5 to both sides
x^2-4x+5=0
a=1,b=-4,c=5
b^2-4ac=(-4)^2-4(1)(5)=16-20=-4
which means the equation has two imaginary soultions
Answer:
I think it might be C but I'm not 100% sure!
Step-by-step explanation:
You have to find a line of best fit (a line through the dots) but it's kind of tricky to do that so I think it's probably C but it could also be A. Just use your best judgement on this one!
If you would like to solve 2x + 5y = - 13 and 3x - 4y = -8, you can do this using the following steps:
<span>2x + 5y = -13 /*4
3x - 4y = -8 /*5
</span>_________________
8x + 20y = -52
15x - 20y = -40
_________________
8x + 15x + 20y - 20y = -52 - 40
23x = -92 /23
x = -92 / 23
x = -4
<span>2x + 5y = -13
</span>2 * (-4) + 5y = -13
-8 + 5y = -13
5y = -13 + 8
5y = -5
y = -1
(x, y) = (-4, -1)
The correct result would be D.) <span>(-4, -1).</span>
