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Marina CMI [18]
3 years ago
11

An amusement park studied methods for decreasing the waiting time (minutes) for rides by loading and unloading riders more effic

iently. Two alternative loading/unloading methods have been proposed. To account for potential differences due to the type of ride and the possible interaction between the method of loading and unloading and the type of ride, a factorial experiment was designed. Use the following data to test for any significant effect due to the loading and unloading method, the type of ride, and interaction. Use . Factor A is method of loading and unloading; Factor B is the type of ride. Type of Ride Roller Coaster Screaming Demon Long Flume Method 1 40 53 46 42 45 42 Method 2 44 48 47 46 44 43
Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
4 0

Step-by-step explanation:

ANOVA table Source SS df MS F

p-value Factor 1 12.00 1 12.000 1.20 .3153

Factor 2 8.00 2 4.000 0.40 .6870 Interaction 56.00 2 28.000 2.80 .1384

Error 60.00 6 10.000 Total 136.00 11

Since the p -value for Factor A is greater than 0.1, therefore Factor A is not significant. The p -value for Factor B is greater than 0.1, therefore Factor B is not significant. It should be noted that for P-value of both Factor and Factor B to be significant, each factor must not be greater than 0.1

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Vitek1552 [10]

Answer:

4$

Step-by-step explanation:
The ratio between the $5.80 spent for 58 text messages is $0.10. This means that each text message sent is $0.10. So you just multiply $0.10 and 40 text messages to find that it costs $4 to send 40 messages.

3 0
2 years ago
Given f(x)=4x^3+7x^2-7x-10 factor f(x), given that -1 is a zero
stira [4]
If - 1 is a zero then
(x + 1)
is a factor.

Dividing with this factor using the long division approach, we get the quadratic factor to be,

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We can rewrite the polynomial as
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We can further factor as

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That is

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7 0
4 years ago
A sheet of glass has a density of 2.5 g/cm3. what is the density of the glass in kg/m3
asambeis [7]

Answer:

this is ez

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Thus, the conversion of 2.5 g/cm3 to kg/m3 would be 2.5x10-3 kg/10-6 m3 = 2.5x103 kg/m3 = 2500 kg/m3

7 0
3 years ago
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Answer:

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Step-by-step explanation:

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