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Marina CMI [18]
3 years ago
11

An amusement park studied methods for decreasing the waiting time (minutes) for rides by loading and unloading riders more effic

iently. Two alternative loading/unloading methods have been proposed. To account for potential differences due to the type of ride and the possible interaction between the method of loading and unloading and the type of ride, a factorial experiment was designed. Use the following data to test for any significant effect due to the loading and unloading method, the type of ride, and interaction. Use . Factor A is method of loading and unloading; Factor B is the type of ride. Type of Ride Roller Coaster Screaming Demon Long Flume Method 1 40 53 46 42 45 42 Method 2 44 48 47 46 44 43
Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
4 0

Step-by-step explanation:

ANOVA table Source SS df MS F

p-value Factor 1 12.00 1 12.000 1.20 .3153

Factor 2 8.00 2 4.000 0.40 .6870 Interaction 56.00 2 28.000 2.80 .1384

Error 60.00 6 10.000 Total 136.00 11

Since the p -value for Factor A is greater than 0.1, therefore Factor A is not significant. The p -value for Factor B is greater than 0.1, therefore Factor B is not significant. It should be noted that for P-value of both Factor and Factor B to be significant, each factor must not be greater than 0.1

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Consider a sequence that follows a minus 5 pattern: 30, 25, 20, 15, ….
Diano4ka-milaya [45]

Answer:

a_2_0=-65

Step-by-step explanation:

As we can see, the sequence starts from 30 and decreases by 5 each time. So, one possible formula for that sequence could be:

a_n=35-5n\hspace{10}n\in N

Let's confirm the formula by evaluating the first 4 terms:

a_1=35-5(1)=35-5=35\\a_2=35-5(2)=35-10=25\\a_3=35-5(3)=35-15=20\\a_4=35-5(4)=35-20=15

Finally evaluating n=20:

a_2_0=35-5(20)=35-100=-65

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csin%20%5Cfrac%7B%20%5Cpi%20x%7D%7B6%7D%20%3D%20x%5E%7B2%7D%20-6x%2B10" id="TexFormula1" tit
Rainbow [258]
The range of the sine function is [-1,1], so:

x^2-6x+10\geq-1 \wedge x^2-6x+10 \leq1\\\\&#10;x^2-6x+10\geq-1\\&#10;x^2-6x+11\geq0\\&#10;\Delta=(-6)^2-4\cdot1\cdot11=36-44=-8\\&#10;x\in \mathbb{R}\\\\&#10;x^2-6x+10\leq1\\&#10;x^2-6x+9\leq0\\&#10;(x-3)^2\leq0\\&#10;(x-3)^2=0\\&#10;x-3=0\\&#10;x=3\\\\&#10;x\in \mathbb{R} \wedge x=3\\&#10;x=3&#10;

So 3 is the only possible value the function x^2-6x+10 can take as an argument. Let's see if 3 is a solution.

\sin\dfrac{\pi\cdot3}{6}=3^2-6\cdot3+10\\&#10;\sin \dfrac{\pi}{2}=9-18+10\\&#10;1=1&#10;

Therefore it is :)
5 0
3 years ago
|3x-4|+5&lt;27 how do you work this?
RUDIKE [14]
You first make your -4 positive because those brackets represent absolute value , so everything between those brackets has to be positive .now that the four positive you can now multiply 4 x 3 which equals 12 , now add 12 + 5 which equals 17 , so 17 is less than 27 (17<27)
6 0
4 years ago
Please help! Please explain and actually help!
stealth61 [152]

Answer:

17

Step-by-step explanation:

According to the Pythagorean theorem, a^2+b^2=c^2, where a and b are the two legs of a right triangle, and c is the hypotenuse. In this scenario, the two legs are 8 and 15, and we are asked to find the hypotenuse. Plugging the two values in, we have 64+225=c^2, where 64 is 8 squared and 225 is 15 squared. Adding, we have the two values as 289. If you don't know your squares, I suggest you take a look at a list or even memorize your squares until 30, but 289 is actually 17 squared. If c^2=289, then c = \sqrt{289}, which is 17.

7 0
3 years ago
Read 2 more answers
Edward drove 275 miles in 212 hours and 357.5 miles in 314 hours. If he drove at a constant rate, how much distance did he trave
bezimeni [28]

Answer: 1.2 Miles

Step-by-step explanation:

Add total miles together: 275 + 357.5 = 632.5 miles total

Add total hours together: 212 + 314 = 526 hours total

Divide total miles driven by total time:

632.5 ÷ 526 = 1.20247147843 miles an hour

7 0
3 years ago
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