Help Solving Exponential Functions
2 answers:
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Answer:
All the answers are given below.
Step-by-step explanation:
(i) (x+3)(x-3) =x² -3² =x² -9 {Since (a+b)(a-b) =a² -b²}
(ii) (x²-3)(x²+3) =(x²)² -3² = {Since (a+b)(a-b) =a² -b²}
(iii)
(iv) (x-3)(x²-9)(x+3) =(x²-9)(x²-9)=(x²-9)²={Since, (a-b)² =a²-2ab+b²}
(v) (x²+y²)(x²-y²) = (x²)² -(y²)² =
(vi) (x²+y²)² = {Since (a+b)² =a²+2ab+b²}
(vii) (x-y)²(x+y)² =(x²-y²)² = {Since (a-b)² =a²-2ab+b² and (a+b)(a-b) =a²-b²}
(viii) (x-y)²(x²+y²)²(x+y)² =(x²+y²)²(x²-y²)² = (Answer)