Answer:
Part 1) m∠1=45°
Part 2) m∠3=45°
Part 3) m∠2=135°
Part 4) m∠4=135°
Step-by-step explanation:
we know that
m∠1=m∠3 -----> by vertical angles Equation A
m∠2=m∠4 -----> by vertical angles Equation B
m∠1+m∠2=180° ----> by supplementary angles (linear pair) Equation C
3(m∠1+m∠3) = m∠2+m∠4 ----> Equation D
Substitute equation A and equation B in equation D
3(m∠1+m∠1) = m∠2+m∠2
6(m∠1) = 2m∠2
3(m∠1) =m∠2 -----> equation E
Substitute equation E in equation C and solve for m∠1
m∠1+3(m∠1)=180°
4(m∠1)=180°
m∠1=45°
<em>Find the measure of m∠3</em>
Remember that
m∠1=m∠3 (equation A)
therefore
m∠3=45°
<em>Find the measure of m∠2</em>
Remember that
m∠2=3(m∠1) (equation E)
substitute the value of m∠1
m∠2=3(45°)=135°
<em>Find the measure of m∠4</em>
Remember that
m∠2=m∠4 (equation B)
therefore
m∠4=135°
It gives you the distance - 7.8
Put the numbers in order
6,7,15,36,41,43,47,49
Q1 = (7 + 15) / 2 = 22/2 = 11 <== first quartile
Q2 = (36 + 41) / 2 = 77/2 = 38.5 <== median
Q3 = (43 + 47) / 2 = 90/2 = 45 <== third quartile
difference of largest value and median.....(49 - 38.5) = 10.5
Answer:
Distance = -7.6
Step-by-step explanation:
Using Distance Formula, √((x2-x1)^2 + (y2-y1)^2)
√((-7 - 0))^2 + (-3 - 0)^2) = 7.6