Question

. Consider the following reaction: CH4(g) + 2 H2S(g) ⇌ CS2(g) + 4 H2(g) A reaction mixture initially contains 0.50 M CH4 and 0.75 M H2S. If the equilibrium concentration of H2 is 0.44 M, find the equilibrium constant (Kc) for the reaction.

Answer 1

Answer:

0.0376

Explanation:

                         CH4(g) + 2 H2S(g) ⇌ CS2(g) + 4 H2(g)

start                   0.5           0.75              0              0

change             -0.11         -0.22           +0.11        +0.44

equilibrium       0.39         0.53             0.11         0.44

$K_{c}=\frac{products}{reactants} =\frac{[CS_{2}][H_{2}]^{4}}{[CH_{4}][H_{2}S]^{2}}=\frac{[0.11][0.44]^{4}}{[0.39][0.53]^{2}} =0.0376$