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Alex73 [517]
3 years ago
14

How many moles of oxygen are in 2.00 moles of NaCIO4?​

Chemistry
1 answer:
Klio2033 [76]3 years ago
3 0

Answer: 8 Moles of Oxygen

Explanation: The formula shows that there are (exactly) 4 oxygen atoms in each mole or formula unit. Therefore 4 * 2.00 = 8.

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A 5.2 molal aqueous solution of methyl alcohol, CH3OH, is supplied. What is the mole fraction of methyl alcohol in the solution?
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Answer:

0.086

Explanation:

A 5.2 molal aqueous solution of methyl alcohol indicates that 5.2 moles of methyl alcohol are present in 1 kilogram (or 1000 g) of water. Water has a molecular weight of 18 g/mol.

(100g)/18g/mol=55.56 mol

5.2 mol/(5.2mol+55.56 mol)=0.086

4 0
2 years ago
DUE IN 30 MINUTES!!! (please keep it short if you can, if not its ok.) What is the molar mass of Pb(SO4)2? Explain how you calcu
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Answer:

399

Explanation:

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What is an atom?explain it plz.
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The table lists the chemical formulas or symbols of a few common substances. Which two substances are compounds? A) aluminum and
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Calculate the molar solubility of CaF2 in a 0.25 m solution of NaF(aq).
Kipish [7]

Answer:

6.4 × 10^-10 M

Explanation:

The molar solubility of the ions in a compound can be calculated from the Ksp (solubility constant).

CaF2 will dissociate as follows:

CaF2 ⇌Ca2+ + 2F-

1 mole of Calcium ion (x)

2 moles of fluorine ion (2x)

NaF will also dissociate as follows:

NaF ⇌ Na+ + F-

Where Na+ = 0.25M

F- = 0.25M

The total concentration of fluoride ion in the solution is (2x + 0.25M), however, due to common ion effect i.e. 2x<0.25, 2x can be neglected. This means that concentration of fluoride ion will be 0.25M

Ksp = {Ca2+}{F-}^2

Ksp = {x}{0.25}^2

4.0 × 10^-11 = 0.25^2 × x

4.0 × 10^-11 = 0.0625x

x = 4.0 × 10^-11 ÷ 6.25 × 10^-2

x = 4/6.25 × 10^ (-11+2)

x = 0.64 × 10^-9

x = 6.4 × 10^-10

Therefore, the molar solubility of CaF2 in NaF solution is 6.4 × 10^-10M

8 0
4 years ago
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