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umka2103 [35]
3 years ago
6

Aidan works a different number of hours each week, depending on whether he is needed or not. For the last nine weeks, he has wor

ked the following number of hours.
1, 3, 1, 1, 4, 5, 8, 6, 5

Which measure of central tendency would be the most effective for Aidan to use if he wants to demonstrate to his supervisor that he hasn't worked very many hours recently?
Answers
mean
median
mode
Mathematics
1 answer:
Sophie [7]3 years ago
5 0

Answer:

Mean (Average) 3.7777777777778

Median 4

Range 7

Mode 1, appeared 3 times

Geometric Mean 2.8976123026694

Largest 8

Smallest 1

Sum 34

Count 9

Step-by-step explanation:

Im bored so i gave you everything

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Find a positive number for which the sum of it and its reciprocal is the smallest​ (least) possible. Let x be the number and let
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Answer:

S(x) = x + \frac{1}{x} --- Objective function

Interval = \{x:x=1\}

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

x + \frac{1}{x}

Hence, the objective function is:

S(x) = x + \frac{1}{x}

To get the the interval, we start by differentiating w.r.t x

<em>Using first principle, this gives:</em>

S'(x) = 1 - \frac{1}{x^2}

Equate S'(x) to 0 in order to solve for x

0 = 1 - \frac{1}{x^2}

Subtract 1 from both sides

0 -1 = 1 -1 - \frac{1}{x^2}

-1 = - \frac{1}{x^2}

Multiply both sides by -1

1 = \frac{1}{x^2}

Cross Multiply

x^2 * 1 = 1

x^2  = 1

Take positive square root of both sides because x is positive

\sqrt{x^2} = \sqrt{1

x = 1

Representing x using interval notation, we have

Interval = \{x:x=1\}

To get the smallest sum, we substitute 1 for x in S(x) = x + \frac{1}{x}

S(1) = 1 + \frac{1}{1}

S(1) = 1 + 1

S(1) = 2

<em>Hence, the smallest sum is 2</em>

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4 years ago
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Answer:

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Step-by-step explanation:

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4 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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PO = OR = 4 cm

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Similarly,

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So, SQ = 6 cm

To measure side, formula is

a = √p^2 + q^2 / 2

a = √6^2 + 8^2 / 2

a = √36+64 / 2

a = √100 / 2

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