All categories

3 years ago

Express each of the following in a+bi form. a)(2 +5i)+(4 +3i)b)(−1+2i) − (4 − 3i)c)(5+3i)(3 +5i)d)(1 +i)(2 − 3i) +3i(1− i) − i

Mathematics

1 answer:

juin [17]3 years ago

6 0

Answer:

a 6+ 8i

b -5 + 5i

c 34i

d 8 + i

Step-by-step explanation:

<em>Add them together </em>6 + 8i

<em>Add them together </em>-5 + 5i

<em>Multiply it out</em> 15 + 25i + 9i + 15 $i^{2}$

<em>Add them together ( $i^{2}$ = the number times -1) </em> 34i

<em>Multiply it out</em> (2 - 3i + 2i - 3 $i^{2}$ ) + (3i - 3 $i^{2}$ ) - i

<em>Add what is in the parenthesis together ( $i^{2}$ = the number times -1) </em>(5 - i) + (3 + 3i) - i

<em>Add them together </em>8 + i

You might be interested in

Select the correct answer from the drop-down menu.

ELEN [110]

Missing term = –2xy

Solution:

Let us first find the quotient of $-8x^2y^3 \div xy$ .

$-8x^2y^3 \div xy=\frac{-8x^2y^3 }{xy}$

$=\frac{-8\times x\times x\times y\times y\times y}{xy}$

Taking common term xy outside in the numerator.

$=\frac{xy(-8\times x\times y\times y)}{xy}$

Both xy in the numerator and denominator are cancelled.

$=-8xy^2$

Thus, the quotient of $-8x^2y^3 \div xy$ is $-8xy^2$ .

Given the quotient of $-8x^2y^3 \div xy$ is same as the product of 4xy and ____.

$-8xy^2=4xy$ × missing term

Divide both sides by 4xy, we get

⇒ missing term = $\frac{-8xy^2}{4xy}$

Cancel the common terms in both numerator and denominator.

⇒ missing term = –2xy

Hence the missing term of the product is –2xy.

4 0

3 years ago

What is the DOMAIN of this graph?

Ksenya-84 [330]

Answer:

Is yellow

Step-by-step explanation:

an open circle for "less than" or "greater than", and a closed circle for "less than or equal to"

6 0

3 years ago

Find lcm of 10x^2 , 30xy^2

AnnyKZ [126]

Answer:

30 x ^2 y ^2

Step-by-step explanation:

3 0

3 years ago

What is the sum of 6 and g

kirza4 [7]

6+g

Sum = addition
........

6 0

3 years ago

Read 2 more answers

Suppose the force acting on a column that helps to support a building is a normally distributed random variable X with mean valu

Sauron [17]

Answer:

(1) 0.4207

(2) 0.7799

Step-by-step explanation:

Given,

Mean value,

$\mu = 15.0$

Standard deviation,

$\sigma = 1.25$

(1) P(X ≥ 17.5) = 1 - P( X ≤ 17.5)

$= 1- P(\frac{x-\mu}{\sigma} \leq \frac{17.5-\mu}{\sigma})$

$=1-P(z\leq \frac{17.5 - 15}{1.25})$

$=1-P(z\leq \frac{2.5}{1.25})$

$=1-P(z\leq 2)$

$=1- 0.5793$ ( By using z-score table )

= 0.4207

(2) P(14 ≤ X ≤ 18) = P(X ≤ 18) - P(X ≤ 14)

$=P(z\leq \frac{18 - 15}{1.25}) - P(z\leq \frac{14 - 15}{1.25})$

$=P(z\leq \frac{3}{1.25}) - P(z\leq -\frac{1}{1.25})$

$=P(z\leq 2.4) - P(z\leq -0.8)$

= 0.9918 - 0.2119

= 0.7799

8 0

3 years ago