60 points and brainlyiest!! Hurry

Please Solve this, it would be extremely helpful for me.

Sidana [21]

Answer:

Step-by-step explanation:

1) ΔCPD & ΔEPF

∠CPD = ∠EPF { Vertically opposite angles}

∠CDP = ∠PFE {CD║EF, FD is transversal, Alternate interior angles are equal}

ΔCPD ≈ΔEPF {AA criteria for similarity }

$\frac{DC}{EF} =\frac{PC}{EP}\\\\\\\frac{27}{EF}=\frac{15}{7.5}\\\\$

Cross multiply

EF * 15 = 27 * 7.5

$EF =\frac{27*7.5}{15}\\\\$

EF = 27 * 0.5

EF = 13.5 cm

ii) EF // AB, so Triangles ACB & ECF are similar triangles

$\frac{AB}{EF}=\frac{AC}{EC}\\\\\frac{22.5}{13.5}=\frac{AC}{22.5}$

$AC= \frac{22.5*22.5}{13.5}\\\\AC=37.5 cm$

AC = 37.5 cm

6 0

2 years ago

Kelsey is putting on sunscreen. She uses 3 ml to cover 45cm to the power of 2 of her skin. She want to know how many milliliters

Artemon [7]

Answer: She would require 16 ml cover 240cm^2 of her skin

Step-by-step explanation:

Let m represent the milliliters of sunscreen required to cover her skin.

Let a represent the area of her skin that was covered. She assumes the the relationship between milliliters of sunscreen and the area is proportional. Introducing the constant of variation, k, the expression becomes

m = ka

She uses 3 ml to cover 45cm^2 of her skin. Therefore,

3 = k × 45

k = 3/45 = 1/15

The expression becomes

m = a/15

The milliliters of sunscreen that Kelsey needs to cover 240cm to the power of 2 of her skin would be

m = 240/15

m = 16 ml

4 0

3 years ago

2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de

Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let $(x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)$

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

⇒ $d=\sqrt{(2-5)^2+(4-3)^2}$

⇒ $d=\sqrt{9+1}$

⇒ $d=\sqrt{10}$ ....(1)

Now, we find the length of M'K'

let $(x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)$

$d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}$

⇒ $d^{'}=\sqrt{(-2+5)^2+(3-4)^2}$

⇒ $d^{'}=\sqrt{9+1}$

⇒ $d^{'}=\sqrt{10}$ .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct

3 0

2 years ago

Read 2 more answers

What is a good estimate for 380% of 20

Ostrovityanka [42]

Answer:

380 divided by 20 is your answer

Step-by-step explanation:

7 0

1 year ago

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GOOD MORNING! ＼(:0:)／

Elza [17]

Answer:

Good morning.

Step-by-step explanation:

ค้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้ ฏ๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎ํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํํ ค้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้ ฏ๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎\ค้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้้ ฏ๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎๎

8 0

1 year ago

Read 2 more answers